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2 years ago

Round off 13,486 to the nearest hundred.

Mathematics

2 answers:

natima [27]2 years ago

5 0

Answer:

13,500

Step-by-step explanation:

timama [110]2 years ago

4 0

Answer: 13,500

Step-by-step explanation:

So the 4 is in the hundred place than u look to the right where the next digit is which is 8. If its 5 or more u round up but if its 5 or less it stays the same. So 8 is 5 or more than u round up the 4 to 5 and leave the rest of the digit 0's. but u leave the 13 the same. If that makes sense.

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ACCTUALLY HELP ME??!!!!!!! NEEDED FOR TOMORROW AND 50 POINTS! will award brainliest for first answer!!

drek231 [11]

Answer:

a:c = 35:24

a:c = 20:27

a:c = 35:22

a:c = 28:27

Step-by-step explanation:

a:b = 7:3

Using cross products

3a = 7b

Divide by 7

3a/7 = b

Now we want

8b = 5c

Substitute in 3a/7 for b

8 (3a/7) = 5c

24/7a = 5c

Multiply by 7

24/7a *7 = 5*7c

24a = 35c

Divide by c

24 a/c = 35

Divide by 24

a/c = 35/24

a:c = 35:24

a:b = 4:9

Using cross products

9a = 4b

Divide by 4

9a/4 = b

Now we want

3b = 5c

Substitute in 9a/4 for b

3 (9a/4) = 5c

27/4a = 5c

Multiply by 4

27/4a *4 = 5*4c

27a = 20c

Divide by c

27 a/c = 20

Divide by 27

a/c = 20/27

a:c = 20:27

b:c = 5:11

Using cross products

11b = 5c

Divide by 11

b = 5c/11

Now we want

2a = 7b

Substitute in 5c/11 for b

2a = 7(5c/11)

2a = 35c/11

Multiply by 11

2a*11 = 35c

22a = 35c

Divide by c

22 a/c = 35

Divide by 22

a/c = 35/22

a:c = 35:22

b:c = 14:3

Using cross products

3b = 14c

Divide by 3

b = 14c/3

Now we want

9a = 2b

Substitute in 14c/3 for b

9a = 2(14c/3)

9a = 28c/3

Multiply by 3

9a*3 = 28c

27a = 28c

Divide by c

27 a/c = 28

Divide by 27

a/c = 28/27

a:c = 28:27

7 0

3 years ago

Chris has 115$ to spend at a shopping mall . If he decides to spend $42 on clothing and $37 on food how much money will he have

Katena32 [7]

Answer:

$36 left

Step-by-step explanation:

42+37=79

115-79=36

7 0

2 years ago

1. What is the value of x? Show all of your work.

Colt1911 [192]

You can use the pathagorean theorm.
$a^2 + b^2 = c^2$
$a^2 + 6^2 = \sqrt{117}^2$
$a^2 + 36 = 117$
$a^2 = 117 - 36$
$a^2 = 81$
$\sqrt{a^2} = \sqrt{81}$
$a = 9$
x = 9

5 0

3 years ago

[-85) x (-29) + 85<br><br> distributive property <br> someone please <br> solve it

avanturin [10]

$(-85) \times (-29) + 85 \\ \\ 2465 + 85 \\ \\ 2550.$