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coldgirl [10]
3 years ago
7

In two or more complete sentences, explain the theorem used in solving for the range of possible lengths of the third side, AB o

f triangle ABC
Mathematics
2 answers:
LenaWriter [7]3 years ago
8 0

Answer:


Step-by-step explanation:

In triangle if two sides are known and included angle is known we can use cosine formula as follows:

Say in a triangle, sides a,b are known and also included angle C

Then the third side

c^{2} =a^{2}+b^{2} -2abCos C

Since all values on right side are known, we can find the third side c easily.

Case II:

If alternately two sides and one angle not included is known. i.e we know a,b and either angle A or B.

then to find third side we use sine formula.

\frac{a}{sinA}=\frac{b}{sinB} =\frac{c}{sinC}

Using the above we can find the unknonwn side c easily.

Luden [163]3 years ago
3 0
You can use the Pythagorean Theorem to find the length of the third side AB (Identified as "x" in the figure attached in the problem), which says that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the legs:
 a² = b²+c²
 As we can see the figure, the triangle does not have an angle of 90°, but it can be divided into two equal parts, leaving two triangles with a right angle. We already have the values of the hypotenuse and a leg in triangle "A" , so we can find the value of the other leg:
 b = √(a²-c²) b = √(10²-4²) b = 9.16
 With these values, we can find the hypotenuse in the triangle "B": x = √b²+c² x = √(9.16)²+(4)² x = 10
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9/10-1/3-1/5 find the fraction
Zanzabum
Find a common multiple in between the denominators.
10 and 3 and 5 -> the least common multiple is 30.

Change all the denominators to 30 by multiplying the top and bottom by the same number.

9/10=27/30
1/3=10/30
1/5=6/30

Subtract!
27/39-10/30-6/30=11/30

The answer is 11/30

Hope this helps!



3 0
3 years ago
Find the interval(s) of upward concavity on this accumulation function.
maxonik [38]

\displaystylef(x)=\int_{0}^{x^2}\sec^2(\sqrt{x})dx \\=\int_{0}^{\sqrt{x^2}}\sec^2(u)\cdot2udu \\=2\int_{0}^{\sqrt{x^2}}\sec^2(u)du \\=2\Big[u\tan(u)-\int\tan(u)du\Big]_{0}^{\sqrt{x^2}} \\=2\Big[u\tan(u)+\ln\Big(\mathrm{abs}(\cos(u))\Big)\Big]_0^x \\=2\Big(x\tan(x)+\dfrac{1}{2}\ln\Big(\cos^2(x)\Big)\Big) \\=2x\tan(x)+\ln(\cos^2(x))

Hope this helps.

6 0
3 years ago
Please help! Can someone please help me with numbers 5 & 7?
MariettaO [177]

Answer:

Infinity minus 9 is infinity-9

Step-by-step explanation:

8 0
2 years ago
Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.
lubasha [3.4K]

Answer:

The answer is option C.

<h3>-6, -5 2/5, -4 1/5</h3>

Step-by-step explanation:

The arithmetic sequence is given by

A(n) =  - 6 + (n - 1)( \frac{1}{5} )

where n is the number of terms

<u>For</u><u> </u><u>the</u><u> first</u><u> </u><u>term</u>

n = 1

So we have

A(1) =  - 6 + (1 - 1)( \frac{1}{5} )

=  - 6 + (0)( \frac{1}{5} )

=  - 6

<u>For</u><u> </u><u>the</u><u> </u><u>fou</u><u>rth</u><u> term</u>

n = 4

A(4) =  - 6 + (4 - 1)( \frac{1}{5} )

=  - 6 + (3)( \frac{1}{5} )

=  - 5 \frac{2}{5}

<u>For</u><u> </u><u>the</u><u> </u><u>tenth</u><u> </u><u>term</u>

n = 10

A(10) =  - 6 + (10 - 1)( \frac{1}{5} )

=  - 6 + (9)( \frac{1}{5} )

=  - 4 \frac{1}{5}

Hope this helps you

4 0
3 years ago
six friends are going to the state fair.The cost of one admission is $9.50, and the cost for one ride on the Ferris wheel is $1.
larisa86 [58]

We are given

total number of friends =6

the cost of one admission is $9.50

now, we can find total cost for admission

total cost for admission= total number of friends*cost of one admission

total cost for admission=6*9.50

we are given

cost for one ride on the Ferris wheel is $1.50

now, we can find total cost for Ferris wheel ride

total cost for Ferris wheel ride= total number of friends*cost of one ride

total cost for Ferris wheel ride=6*1.50

now, we can find total cost

total cost =total cost for admission+total cost for Ferris wheel ride

total cost=6*9.50+6*1.50

now, we can solve it

total cost=6(9.50+1.50)

total cost=6*11

total cost=66

so, the total cost is $66...........Answer


3 0
3 years ago
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