The molarity = 1.716 M
<h3>Further explanation</h3>
Given
25 ml ethanol
d = 0.789 g/ml
250 ml solution
Required
The molarity
Solution
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

mass of ethanol :
= 25 ml x 0.789 g/ml
= 19.725 g
mol ethanol :
= 19.725 g : 46 g/mol
= 0.429
The molarity :
= 0.429 : 0.25 L
= 1.716 M
Answer:
maybe
Explanation:
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Answer:
The answer to your question is letter D
Explanation:
Data
mass of Li = 4.5 g
mass of N₂ = 4.5 g
limiting reactant = ?
Reaction
6Li (s) + N₂ (g) ⇒ 2Li₃N
This reaction is balanced
Process
1.- Calculate the molecular mass of the reactants
Li = 7 x 6 = 42g
N = 14 x 2 = 28 g
Calculate the limiting reactant using proportions
Theoretical proportion Li / N = 42 / 28 = 1.5
Experimental proportion Li/N = 4.5/4.5 = 1
As the experimental proportion was lower than the theoretical, the limiting reactant is Lithium
2.- Calculate the theoretical yield of Li₃N
42 g of lithium -------------- 70 g of Li₃N
4.5 g of lithium ------------- x
x = (4.5 x 70) / 42
x = 315 / 42
<u> x = 7.5 %</u>
Answer:
The answer to your question is: 28°C
Explanation:
Data
mass = 10 g
T1 = 23°C
T2 = ?
Q = 209 joules
Formula
Q = mC(T2 - T1)
T2 = Q/mC + T1
T2 = 209/(10 x 4.182) + 23
T2 = 4.99 + 23
T2 = 27.99 ≈ 28°C