The answer is 8 because if you subtract 8-3 it’s still bigger then 4
Answer:
676000
Step-by-step explanation:
3 digits of the 5-digit code are number 0-9 which is 10 numbers that could go into that spot, after the three digits there are two letters and because there are 26 letters in the alphabet you would multiply 10*10*10*26*26 which equals 676000
Answer:
f(2) = 32
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 3x² + 2x + 16
f(2) is x = 2
<u>Step 2: Evaluate</u>
- Substitute: f(2) = 3(2)² + 2(2) + 16
- Evaluate: f(2) = 3(4) + 2(2) + 16
- Multiply: f(2) = 12 + 4 + 16
- Add: f(2) = 32
And we have our answer!
Answer:
If we arrange the talks from the lowest starting time to the highest ending time we get total of 11 talks.
using algorithm 7 we get answer (1) - (3) - (6) - (9) the largest number of talks scheduled.
Step-by-step explanation:
arranging the talks from lowest starting time to the highest ending time.
thus,
- 9:00 a.m. and 9:45 a.m.
- 9:30 a.m. and 10:00 a.m.
- 9:50 a.m. and 10:15 a.m.
- 10:00 a.m. and 10:30 a.m.
- 10:10 a.m. and 10:25 a.m.
- 10:30 a.m. and 10:55 a.m.
- 10:15 a.m. and 10:45 a.m.
- 10:30 a.m. and 11:00 a.m.
- 10:45 a.m. and 11:30 a.m.
- 10:55 a.m. and 11:25 a.m.
- 11:00 a.m. and 11:15 a.m.
we start from the earliest time as
9:00 a.m. and 9:45 a.m which is (1).
After the talk is finished we pick the nearest time for another talk which starts at
9:50 a.m. and 10:15 a.m which is (3).
After this talk we again pick the nearest time for another talk which becomes
10:30 a.m. and 10:55 a.m which is (6).
and lastly
10:45 a.m. and 11:30 a.m which is (9).
Note: we didn't choose other times because we cannot talk at 2 or 3 places at the same time. so we pick another when one talk is finished.
thus the answer is (1) - (3) - (6) - (9) as the largest number of talks scheduled.
Answer:
slope = 0
Step-by-step explanation:
Calculate the slope m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 7, - 8) and (x₂, y₂ ) = (5, - 8)
m = 
= 
= 0
