1.41 is the magnitude and -45° is the direction
The author's purpose is to persuade
Answer:
Part A:
Time taken by the snake to reach its top speed is 1.28571 sec.
Part B:
Snake travels 2.0828 m in that time
Part C:
Mongoose have a chance to catch the black mamba
Explanation:
Part A:
According to first equation of motion:
![v_f=at+v_i](https://tex.z-dn.net/?f=v_f%3Dat%2Bv_i)
v_f is top speed
v_i is initial or minimum speed
t is time
a is acceleration
![3.24=(2.52)t+0\\t=1.28571 sec](https://tex.z-dn.net/?f=3.24%3D%282.52%29t%2B0%5C%5Ct%3D1.28571%20sec)
Time taken by the snake to reach its top speed is 1.28571 sec
Part B:
According to Second equation of motion:
![S=v_it+\frac{1}{2}at^2](https://tex.z-dn.net/?f=S%3Dv_it%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2)
v_i=0
![S=0.5(2.52)(1.28571)^2\\S=2.0828 m](https://tex.z-dn.net/?f=S%3D0.5%282.52%29%281.28571%29%5E2%5C%5CS%3D2.0828%20m)
Snake travels 2.0828 m in that time
Part C:
Distance covered by black mamba is 2.0828 m which is less than its length 3.12 m
2.0828 m<3.12 m
Mongoose have a chance to catch the black mamba
If the wave velocity and frequency of a wave are both doubled, the wavelength will remain <u>the same. </u>
<u />
The wavelength of a wave shows the spatial orientation of distance between two successive crest in a wave medium.
The wavelength λ is expressed by using the relation:
![\mathbf{\lambda = \dfrac{v}{f}}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Clambda%20%3D%20%5Cdfrac%7Bv%7D%7Bf%7D%7D)
Now, if velocity and frequency of wave is both doubled, the wavelength will remain <u>the same.</u>
<u />
Learn more about wavelength here:
brainly.com/question/10750459
F = 245N
The Acceleration of an object in a free fall is 9.8 m/s
force= 25kg X 9.8m/s