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mash [69]
3 years ago
8

Why are lunar eclipses more common than solar eclipses

Physics
2 answers:
Nimfa-mama [501]3 years ago
6 0
Lunar eclipses are more common because the moon and sun are not likely to align rather than the planets aligning.
Law Incorporation [45]3 years ago
3 0
<span>Solar eclipses are not actually rarer than lunar eclipses – in fact, they occur in about equal numbers, usually about two of each per year.</span>
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A 1 kg object sits on the earth’s surface. What is the force of gravity between the object and the earth? (mass of the earth = 5
snow_lady [41]

Answer:

9.81N

Explanation:

the force of attraction is given by

F=<u>GmM</u><u>/</u><u>R²</u><u> </u>

where m is mass of the body

M is mass of the earth

R is radius of the earth

G is the universal gravitational constant(6.67x10-¹¹)

hence we substitute the values in the formula.

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3 years ago
A canister is approaching a 78.4 kg astronaut at 3.5 m/s in an airless spacecraft. She pushes against it, which slows it down to
notka56 [123]

Answer:

<h3>76.3 kg</h3>

Explanation:

<h3>this is my week answer</h3>
6 0
3 years ago
Definition of angle of incidence​
Nadusha1986 [10]
The definition of incidence is In geometric optics, the angle of incidence is the angle between a ray incident on a surface and the line perpendicular to the surface at the point of incidence, called the normal.
3 0
3 years ago
4. What would be the mass of #3 in kilograms?
Nezavi [6.7K]

Answer:

0.003

Explanation:

3 is in grammes so you divide by 1000

7 0
3 years ago
The velocity of a 640-kg auto is changed from 10.0 m/s to 44.0 m/s in 71.0 s by an external, constant force. (a) What is the res
n200080 [17]

Answer:

(a) <em>change in momentum of the car = 21760 kgm/s</em>

(b) <em>The magnitude of the force = 306.48 N</em>

Explanation:

<em>(a)</em>

<em>Change in momentum: </em><em>This is the product of mass and change in velocity. The unit of momentum is kgm/s. It can be expressed mathematically as,</em>

Change in momentum of the car = m(v-u)................. Equation 1

Where m = mass of the car, v = final velocity of the car, u = initial velocity of the car.

<em>Given: m = 640 kg, v = 44.0 m/s, u = 10.0 m/s.</em>

<em>Substituting these values into equation 1,</em>

<em>Change in momentum of the car = 640 (44-10)</em>

<em>change in momentum of the car = 640× 34</em>

<em>change in momentum of the car = 21760 kgm/s</em>

<em>change in momentum of the car = 21760 kgm/s</em>

<em>(b) Force:</em><em> Force of a body can be defined as the product of mass and its acceleration. It is measured in Newton (N). It can be expressed mathematically as,</em>

<em>Force = ma ................................ Equation 2</em>

<em> </em><em>    Or</em>

<em>Force = m(v-u)/t...................................... Equation 3</em>

<em>Where m = mass of the car, v = final velocity of the car, u = initial velocity of the car, a = acceleration of the car, t = time taken to change the velocity.</em>

<em>Given: m = 640 kg, u = 10.0 m/s v = 44 m/s, t = 71 s.</em>

<em>Substituting these values into equation 3</em>

<em>Force = 640(44-10)/71</em>

<em>Force = (640×34)/71</em>

<em>Force = 306.48 N</em>

<em>The magnitude of the force = 306.48 N</em>

3 0
3 years ago
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