Answer:
476.387 Hz
714.583 Hz
Explanation:
L = Length of tube
v = Speed of sound in air = 343 m/s
Frequency for a closed tube is given by

The frequency is 476.387 Hz
If it was one third full 

The frequency is 714.583 Hz
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Explanation: Hope this helped. Have a great day!!!!
Answer:
0.2 m/s^2
Explanation:
initial speed 14m/s
final speed 20m/s
acceleration:
(20m/s - 14m /s) /30s = (6m/s)/30s = 0.2 m/s^2
Part A)
As we know that spring force is given by
F = kx
here x = stretch in the spring from natural length
So here when spring reaches to its natural length
Force due to spring = 0
so acceleration = 0
Part b)
When spring is compressed from its natural length it will have elastic potential energy in it
so it is given by

now we know that there is no friction in it so maximum kinetic energy of the launcher must be equal to the elastic potential energy of the spring

here we have
k = 70 N/m
x = 0.4 m


Part c)
Now to find the speed we know that



so its speed is 6.11 m/s