Answer:
-0,2 m/s²
Explanation:
Acceleration = α = (V-V₀)/t
α = (10-14)/20 = -0,2 m/s²
Answer: 313920
Explanation:First, we’re going to assume that the top of the circular plate surface is 2 meters under the water. Next, we will set up the axis system so that the origin of the axis system is at the center of the plate.
Finally, we will again split up the plate into n horizontal strips each of width Δy and we’ll choose a point y∗ from each strip. Attached to this is a sketch of the set up.
The water’s surface is shown at the top of the sketch. Below the water’s surface is the circular plate and a standard xy-axis system is superimposed on the circle with the center of the circle at the origin of the axis system. It is shown that the distance from the water’s surface and the top of the plate is 6 meters and the distance from the water’s surface to the x-axis (and hence the center of the plate) is 8 meters.
The depth below the water surface of each strip is,
di = 8 − yi
and that in turn gives us the pressure on the strip,
Pi =ρgdi = 9810 (8−yi)
The area of each strip is,
Ai = 2√4− (yi) 2Δy
The hydrostatic force on each strip is,
Fi = Pi Ai=9810 (8−yi) (2) √4−(yi)² Δy
The total force on the plate is found on the attached image.
Answer:
Yes, it is possible to add three vectors of equal magnitudes and get zero. This can happen if the resultant of the two vectors are equal and opposite in direction to the third vector.
Answer:
The separation distance between the two charges must be 82704.2925 m
Explanation:
Given:
Two negative charges that are both q = -3.8 C
Force of 19 N
Question: How far apart are the two charges, s = ?
First, you need to get the electrostatic force of this two negative charges:

Here
k = electric constant of the medium = 9x10⁹N m²/C²
Substituting values:

Answer:
<em>Rt = 8 ohm</em>
<em>I = 2 A</em>
<em>Vab = 12 V</em>
<em>VbΓ = 4 V</em>
<em>VaΓ = 16 V</em>
Explanation:
<u>Electric Circuits</u>
We'll apply Ohm's formula to solve the circuit shown on the image:
V = R.I
Where V is the voltage, R is the resistance, and I is the current.
The circuit has two resistances connected in series, thus the total resistance is:
Rt = R1 + R2 = 6 ohm + 2 ohm = 8 ohm
Now the current is:


I = 2 A
The voltages are calculated below:
Vab = R1 * I = 6 ohm * 2 A = 12 V
VbΓ = R2 * I = 2 ohm * 2 A = 4 V
VaΓ = Vab + VbΓ = 12 V + 4 V = 16 V