<span>Mass of the electron = 9.1 x 10 ^ -28g = 9.1 x 10 ^ -31kg
Velocity of the electron = 1.7 x 10 ^ 4
We have Planck Constant h = 6.626 x 10 ^ -34
Wavelength of the electron w = h/mv
w = 6.626 x 10 ^ -34 / ((9.1 x 10 ^ -31)(1.7 x 10 ^ 4))
= 6.626 x 10 ^ -34 / 15.47 x 10 ^ -27
= 0.428312 x 10 ^ -7
= 4.28 x 10 ^ -8 m</span>
Answer:
It is virtual and behind the mirror
Explanation:
When an image is produced by a mirror, we have the following situations:
- The image is said to be in front of the mirror if it is on the same side of the object, with respect to the mirror
- The image is said to be behind of the mirror if it is on the opposite side of the object, with respect to the mirror
Moreover:
- The image is said to be real if it is in front of the mirror
- The image is said to be virtual if it is behind the mirror
In this case, the image (located at point I) is on the opposite side of the object (located at point O), so it is virtual and behind the mirror.
The final vertical velocity of the object is 705.6 m
Explanation:
Here we have to analyze the vertical motion of the object, which is a free fall motion, with constant acceleration of
towards the ground due to gravity.
Therefore, we can use the following suvat equation:
where
v is the final vertical velocity
u is the initial vertical velocity
is the acceleration
t is the time
Since the object is dropped,
u = 0
Therefore, the magnitude of the vertical velocity of the object after t = 72 seconds is:
Learn more about free fall:
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#LearnwithBrainly
Answer:
The right approach will be Option C "Group 12".
Explanation:
- A table that further arranges the chemical components in addition to expanding the electron configuration. Elements possessing identical characteristics are positioned in almost the same section (column or group), although elements in almost the same row become positioned with a similar amount of electron spheres.
- Group 12 components therefore partially replaced (n − 1)d subshells, and therefore aren't metals, technically accurate. However, although much their chemistry seems to be comparable to something like the components throughout the d block which includes establishing themselves.
Some other options in question are not relevant to something like the given scenario. Because then the option here is just the right one.
Answer:
Truck's speed = 5.21 m/s
Car's speed = 20.2 m/s
Explanation:
Given:
Mass of truck = M = 1650 kg
Speed of the truck initially = U = 15 m/s
Mass of the car = m = 779 kg
Initial speed of the car =u = 0
From the momentum conservation, Total initial momentum = Total final momentum.
M V+m U = M V +m v
⇒ (1650)(15) + 779×0 = (1650)V + 779 v
⇒ 24750 = 1650 V+779 v →(1)
Since the collision is elastic, relative velocity of approach = relative velocity of separation. 15 = v - V
⇒ v =V + 15; This is now substituted in the equation(1) above.
24750 = 1650 V + (799) (V+15)
⇒ 24750 = 1650 V + 799 V + 11985
⇒ 2449 V = 12765
⇒ Final velocity of the truck = 
= 5.21 m/s
Final velocity of the car = v = V+15 = 5.21 + 15 = 20.2 m/s
