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lorasvet [3.4K]
3 years ago
6

A simple pendulum consists of a point mass suspended by a weightless, rigid wire in a uniform gravitation field. Which of the fo

llowing statements are true when the system undergoes small oscillations?Check all that apply.The period is inversely proportional to the suspended mass.The period is proportional to the square root of the length of the wire.The period is independent of the suspended mass.The period is proportional to the suspended mass.The period is independent of the length of the wire.The period is inversely proportional to the length of the wire.
Physics
1 answer:
alex41 [277]3 years ago
6 0

Answer:

The period is proportional to the square root of the length of the wire.

The period is independent of the suspended mass.

Explanation:

The period of a simple pendulum, in the small angle oscillation approximation, is given by

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration due to gravity

From the formula, we notice the following facts:

- The period is proportional to the square root of the length of the wire, L

- The period is independent of the suspended mass, m

So, these are the two correct statements.

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An astronaut is in equilibrium when he is positioned 140 km from the center of asteroid C and 581 km from the center of asteroid
serg [7]

Answer:B

Explanation:

Given

Distance of astronaut From asteroid x is r_x=140 km

Distance of astronaut From asteroid Y is r_y=581 km

Suppose M,M_x,M_y be the masses of Astronaut , asteroid X and Y

If the astronaut is in equilibrium then net gravitational force on it is zero

F_x=F_y

\frac{GMM_x}{r_x^2}=\frac{GMM_y}{r_y^2}

cancel out the common terms we get

\frac{M_x}{r_x^2}=\frac{M_y}{r_y^2}

\frac{M_x}{M_y}=(\frac{r_x}{r_y})^2

\frac{M_x}{M_y}=(\frac{140}{581})^2

\frac{M_x}{M_y}=0.05806\approx 0.0581

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3 years ago
Which process is associated with an increase in kinetic energy, and what experimental evidence supports this?
Alinara [238K]

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Option B: the period during which a solid is not changing state; its temperature is increasing

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6 0
4 years ago
PLEASE HELP!!!! OFFERING 99 POINTS!!
Nitella [24]

The Gravitational PE (U) depends on three things: the object’s mass (m), its height (h), and gravitational acceleration (g), which is 9.81 m/s^2 on Earth’s surface.

so U = mgh = 9.81mh on earth

mass of the car = 50.0 grams = 0.05kg

height, h:

Hill 1 = 90.0 cm = 0.9m,

Hill 2 = 65.0 cm = 0.65m,

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difference in Gravitational Potential Energy from the top of Hill 1 to the top of Hill 3 = 0.4415 - 0.0981

= 0.3434J where J is the unit for energy, Joules


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