A simple pendulum consists of a point mass suspended by a weightless, rigid wire in a uniform gravitation field. Which of the fo
1 answer:
Answer:
The period is proportional to the square root of the length of the wire.
The period is independent of the suspended mass.
Explanation:
The period of a simple pendulum, in the small angle oscillation approximation, is given by
where
L is the length of the pendulum
g is the acceleration due to gravity
From the formula, we notice the following facts:
- The period is proportional to the square root of the length of the wire, L
- The period is independent of the suspended mass, m
So, these are the two correct statements.
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If he wants to increase power, force must increase and decrease time.
Answer:
The pressure is constant, and it is P = 150kpa.
the specific volumes are:
initial = 0.062 m^3/kg
final = 0.027 m^3/kg.
Then, the specific work can be written as:
The fact that the work is negative, means that we need to apply work to the air in order to compress it.
Now, to write it in more common units we have that:
1 kPa*m^3 = 1000J.
-5.25 kPa*m^3/kg = -5250 J/kg.