2 8 −10−15÷3=2, start superscript, 8, end superscript, minus, 10, minus, 15, divided by, 3, equals
Sergio039 [100]
Answer:
241
Step-by-step explanation:
Given the equation to evaluate :
2^8 −10−15÷3
2^8 = 256
256 - 10 - 15 ÷ 3
From BODMAS principle, we evaluate the divison before subtraction :
-15 ÷ 3 = - 5
256 - 10 -5
256 - 15
= 241
Answer:
(25,12)
Step-by-step explanation:
pattern A=20+5
=25
pattern B=14-2
=12
25,12
9514 1404 393
Answer:
Step-by-step explanation:
The interval of interest becomes the limits of integration. ∆x becomes dx, and the xi are replaced by the variable of integration, x.
Brian (I think you meant Brian haha..) is incorrect because the tenth place is the number right after the decimal which is a 4. If you are rounding to the tenth place that means that you have to look at the number to the right of that, which is 4. 5 and up means you round up and 4 and down means you round down. This is a 4, so you keep the 4 after the decimal and get rid of the last 4. Therefore, when rounded it would be: 4.4.
Hope this helped! Good luck! :)
This is a square matrix whose entries are real and rows and columns are orthogonal unit vectors.
