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3 years ago

50 POINTS AND I WILL MARK BRAINLIEST Find the volume please help

Mathematics

2 answers:

ANEK [815]3 years ago

8 0

Answer:348

Step-by-step explanation:

For composite prisms, where the bases are a composite shape, the area of the bases is the sum of the areas of the parts it is made of. The volume of the composite prism is then given by multiplying the whole base area by the height of the prism.In math, volume is the amount of space in a certain 3D object. For instance, a fish tank has 3 feet in length, 1 foot in width and two feet in height. To find the volume, you multiply length times width times height, which is 3x1x2, which equals six. So the volume of the fish tank is 6 cubic feet.

Fed [463]3 years ago

3 0

Answer:

$1,205.8\: {ft}^{3}$

Step-by-step explanation:

Given object is made up of cylindrical and conical parts.

Fir cylindrical part:

r = 16/2 = 8 ft

h = 4 ft

For conical part:

r = 16/2 = 8 ft

h = 6 ft

Volume of the object = Volume of cylinderical part + Volume of the conical part

$= \pi {r}^{2} h + \frac{1}{3} \pi {r}^{2} h \\ \\ =\pi \times {8}^{2} \times 4 + \frac{1}{3} \times \pi \times {8}^{2} \times 6 \\ \\ = 64\pi \times 4 + \frac{1}{ \cancel3} \times 64\pi \times \cancel6 \\ \\ = 64\pi(4 + 2) \\ \\ = 64\pi \times 6 \\ \\ = 384\pi \\ \\ = 384 \times 3.14 \\ \\ = 1,205.8 \: {ft}^{3}$

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if the sum of the first 60 positive integers is s, what is the sum of the first 120 integers in terms of s? a. 2s 3600 b. s^2 36

kvasek [131]

For the first 60 positive integers, a = 1, n = 60, l = 60.
Sn = n/2(a + l)
s = 60/2(1 + 60) = 30(61)

For the next 60 positive integer, a = 61, n = 60, l = 120
Sum = 60/2(61 + 120) = 30(61 + 120) = 30(61) + 30(120) = s + 3600

Sum of first 120 positive integers = s + s + 3600 = 2s + 3600

6 0

3 years ago

The length of a rectangle is 3 meters longer than the width. if the area is 36 square meters, find the rectangle's dimensions.

kompoz [17]

Here you are. you can see my explication.
have fun

8 0

3 years ago

144kg in the ratio of 9:8:7

ANEK [815]

Step-by-step explanation:

Hey there!

Given;

Ratio = 9:8:7

Let "x" be the common factor. So,

9x+8x+7x = 144

or, 24x = 144

or, x = 144/24

or, x= 6

It's like;

= 9*6:8*6:7*6

= 54:48:42

Therefore, their ratio is 54:48:42.

Hope it helps...

4 0

3 years ago

Match the numerical expressions to their simplest forms.

Aloiza [94]

Answer:

$(a^6b^1^2)^\frac{1}{3}$ = $a^2b^4$

$\frac{(a^5b^3)^\frac{1}{2}}{(ab)^-^\frac{1}{2}}$ = $a^3b^2$

$(\frac{a^5}{a^-^3b^-^4})^\frac{1}{4}$ = $a^2b$

$(\frac{a^3}{ab^-^6})^\frac{1}{2}$ = $ab^3$

Step-by-step explanation:

Simplify each of the expressions:

$(a^6b^1^2)^\frac{1}{3}$

Distribute the exponent. Multiply the exponent of the term outside of the parenthesis by the exponents of the variable.

$(a^6b^1^2)^\frac{1}{3}$

$a^6^*^\frac{1}{3}b^1^2^*^\frac{1}{3}$

Simplify,

$a^2b^4$

Use a similar technique to solve this problem. Remember, a fractional exponent is the same as a radical, if the denominator is (2), then the operation is taking the square root of the number.

$\frac{(a^5b^3)^\frac{1}{2}}{(ab)^-^\frac{1}{2}}$

Rewrite as square roots:

$\frac{\sqrt{a^5b^3}}{\sqrt{(ab)}^-^1}$

A negative exponent indicates one needs to take the reciprocal of the number. Apply this here:

$\frac{\sqrt{a^5b^3}}{\frac{1}{\sqrt{ab}}}$

Simplify,

$\sqrt{a^5b^3}*\sqrt{ab}$

Since both numbers are under a radical, one can rewrite them such that they are under the same radical,

$\sqrt{a^5b^3*ab}$

Simplify,

$\sqrt{a^6b^4}$

Since this operation is taking the square root, divide the exponents in half to do this operation:

$a^3b^2$

$(\frac{a^5}{a^-^3b^-^4})^\frac{1}{4}$

Simplify, to simplify the expression in the numerator and the denominator, the base must be the same. Remember, the base is the number that is being raised to the exponent. One subtracts the exponent of the number in the denominator from the exponent of the like base in the numerator. This only works if all terms in both the numerator and the denominator have the operation of multiplication between them:

$(\frac{a^8}{b^-^4})^\frac{1}{4}$

Bring the negative exponent to the numerator. Change the sign of the exponent and rewrite it in the numerator,

$(a^8b^4)^\frac{1}{4}$

This expression to the power of the one forth. This is the same as taking the quartic root of the expression. Rewrite the expression with such,

$\sqrt[4]{a^8b^4}$

SImplify, divide the exponents by (4) to simulate taking the quartic root,

$a^2b$

$(\frac{a^3}{ab^-^6})^\frac{1}{2}$

Using all of the rules mentioned above, simplify the fraction. The only operation happening between the numbers in both the numerator and the denominator is multiplication. Therefore, one can subtract the exponents of the terms with the like base. The term in the denomaintor can be rewritten in the numerator with its exponent times negative (1).

$(a^3^-^1b^(^-^6^*^(^-^1^)^))^\frac{1}{2}$