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ratelena [41]
3 years ago
11

During a new moon, is the moon A) in between Earth and the sun B) in front of the sun, in back of Earth C) in front of Earth, in

front of the sun D) alongside Earth in front of the sun
Physics
2 answers:
Ira Lisetskai [31]3 years ago
5 0
B. in front of the sun, in back of earth
Lady_Fox [76]3 years ago
4 0

During a new moon, the moon is in between the earth and the sun

Answer: Option A

<u>Explanation:</u>

New moon day also known as solar eclipse that occurs when the moon is located  in between the sun and the earth. In that phase, the sun, moon and earth are in alignment.

Usually they cannot be seen from earth with our naked eyes. Here the sun and the earth will be facing the opposite sides. Hence option B.C and D are irrelevant.

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To what volume will a sample of gas expand if it is heated from 50.0°c and 2.33 l to 500.0°c?
Lena [83]

The volume of the gas at 500^{\circ} \text{C} is \fbox{\begin\ 5.576\,{\text{L}}\\\end{minispace}}.

Further Explanation:

Consider the pressure of the gas to be constant.  

The change in the volume of the gas when the temperature of the gas is varied by keeping the pressure of the gas at a constant value is defined by the Charles' Law.

Concept:

According to the Charles law, the volume of the gas is directly proportional to the temperature of the gas at constant pressure.

The Charles' law can be stated as:

\fbox{\begin\\V\propto T\\\end{minispace}}

The above expression can we written as.

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Convert the temperature of the gas into kelvin.

T=273+T^\circ\text{C}}}

Here, T is the temperature in kelvin and T^\circ\text{C}}} is the temperature in centigrade.  

The initial temperature of the gas is 50^\circ\text{C}. The temperature of the gas in kelvin is.  

\begin{aligned}{T_1}&=273+50\\&=323\,{\text{K}}\\\end{aligned}

The final temperature of the gas is 500^\circ\text{C} . The temperature in kelvin is.  

\begin{aligned}{T_2}&=273+500\\&=773\,{\text{K}}\\\end{aligned}

Substitute the values of temperature and volume in the expression of the Charles' Law.  

\begin{aligned}{V_2}&=\frac{{{T_2}}}{{{T_1}}}{V_1}\\&=\frac{{773\,{\text{K}}}}{{323\,{\text{K}}}}\left({2.33\,{\text{L}}}\right)\\&=5.576\,{\text{L}}\\\end{aligned}

Thus, the volume of the gas at 500^\circ\text{C}} will be \fbox{\begin\ 5.576\,{\text{L}}\\\end{minispace}}.

Learn More:  

1. Examples of wind and solar energy brainly.com/question/1062501

2. Stress developed in a wire brainly.com/question/12985068

Answer Details:  

Grade: High school  

Subject: Physics  

Chapter: Gas law  

Keywords:  

Charles law, temperature, volume, initial, final, kelvin, centigrade, 50 C, 500 degree, 500 C, 50 degree, 2,33 L, gas expand, sample, heated.

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