Frequency? Possibly I’m not 100% sure
It’s helps the heart stay healthier by respiratory of the heart
The acceleration of the air plane is 
<u>Explanation:</u>
Given:
The mass of the air plane = 1492.3 kg
Force of each four engine = 1447.5 N
So, the total force of four engines can be calculated as = 4(1447.5) = 5790 N
The force that acts on the object is equal to the product of mass (m) and its acceleration. It can express by the below formula,

The above equation can be written as below to find acceleration,

Now. Substitute the given values, we get,

Answer:
Not between significant digits.
Explanation:
A zero not significant when it's not between significant digits.
Answer:

Explanation:
According to the law of conservation of linear momentum, the total momentum of both pucks won't be changed regardless of their interaction if no external forces are acting on the system.
Being
and
the masses of pucks a and b respectively, the initial momentum of the system is

Since b is initially at rest

After the collision and being
and
the respective velocities, the total momentum is

Both momentums are equal, thus
Solving for 


The initial kinetic energy can be found as (provided puck b is at rest)


The final kinetic energy is


The change of kinetic energy is
