Answer:
The greater the velocity, the greater the Force needs to be, and the greater the fiction is
Explanation:
I don't know what you are working on so here are a few responses
Answer:
r₂ = 0.316 m
Explanation:
The sound level is expressed in decibels, therefore let's find the intensity for the new location
β = 10 log
let's write this expression for our case
β₁ = 10 log \frac{I_1}{I_o}
β₂ = 10 log \frac{I_2}{I_o}
β₂ -β₁ = 10 (
)
β₂ - β₁ = 10
log \frac{I_2}{I_1} =
= 3
= 10³
I₂ = 10³ I₁
having the relationship between the intensities, we can use the definition of intensity which is the power per unit area
I = P / A
P = I A
the area is of a sphere
A = 4π r²
the power of the sound does not change, so we can write it for the two points
P = I₁ A₁ = I₂ A₂
I₁ r₁² = I₂ r₂²
we substitute the ratio of intensities
I₁ r₁² = (10³ I₁ ) r₂²
r₁² = 10³ r₂²
r₂ = r₁ / √10³
we calculate
r₂ =
r₂ = 0.316 m
Answer:
Velocity, v = 0.239 m/s
Explanation:
Given that,
The distance between two consecutive nodes of a standing wave is 20.9 cm = 0.209 m
The hand generating the pulses moves up and down through a complete cycle 2.57 times every 4.47 s.
For a standing wave, the distance between two consecutive nodes is equal to half of the wavelength.
![\dfrac{\lambda}{2}=0.209\ m\\\\\lambda=0.418\ m](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Clambda%7D%7B2%7D%3D0.209%5C%20m%5C%5C%5C%5C%5Clambda%3D0.418%5C%20m)
Frequency is number of cycles per unit time.
![f=\dfrac{2.57}{4.47}\\\\f=0.574\ Hz](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7B2.57%7D%7B4.47%7D%5C%5C%5C%5Cf%3D0.574%5C%20Hz)
Now we can find the velocity of the wave.
Velocity = frequency × wavelength
v = 0.574 × 0.418
v = 0.239 m/s
So, the velocity of the wave is 0.239 m/s.
Answer
given,
y(x,t)= 2.20 mm cos[( 7.02 rad/m )x+( 743 rad/s )t]
length of the rope = 1.33 m
mass of the rope = 3.31 g
comparing the given equation from the general wave equation
y(x,t)= A cos[k x+ω t]
A is amplitude
now on comparing
a) Amplitude = 2.20 mm
b) frequency =
![f = \dfrac{\omega}{2\pi}](https://tex.z-dn.net/?f=f%20%3D%20%5Cdfrac%7B%5Comega%7D%7B2%5Cpi%7D)
![f = \dfrac{743}{2\pi}](https://tex.z-dn.net/?f=f%20%3D%20%5Cdfrac%7B743%7D%7B2%5Cpi%7D)
f = 118.25 Hz
c) wavelength
![k= \dfrac{2\pi}{\lambda}](https://tex.z-dn.net/?f=k%3D%20%5Cdfrac%7B2%5Cpi%7D%7B%5Clambda%7D)
![\lambda= \dfrac{2\pi}{k}](https://tex.z-dn.net/?f=%5Clambda%3D%20%5Cdfrac%7B2%5Cpi%7D%7Bk%7D)
![\lambda= \dfrac{2\pi}{7.02}](https://tex.z-dn.net/?f=%5Clambda%3D%20%5Cdfrac%7B2%5Cpi%7D%7B7.02%7D)
![\lambda= 0.895\ m](https://tex.z-dn.net/?f=%5Clambda%3D%200.895%5C%20m)
d) speed
![v = \dfrac{\omega}{k}](https://tex.z-dn.net/?f=v%20%3D%20%5Cdfrac%7B%5Comega%7D%7Bk%7D)
![v = \dfrac{743}{7.02}](https://tex.z-dn.net/?f=v%20%3D%20%5Cdfrac%7B743%7D%7B7.02%7D)
v = 105.84 m/s
e) direction of the motion will be in negative x-direction
f) tension
![T = \dfrac{v^2\ m}{L}](https://tex.z-dn.net/?f=T%20%3D%20%5Cdfrac%7Bv%5E2%5C%20m%7D%7BL%7D)
![T = \dfrac{(105.84)^2\times 3.31 \times 10^{-3}}{1.33}](https://tex.z-dn.net/?f=T%20%3D%20%5Cdfrac%7B%28105.84%29%5E2%5Ctimes%203.31%20%5Ctimes%2010%5E%7B-3%7D%7D%7B1.33%7D)
T = 27.87 N
g) Power transmitted by the wave
![P = \dfrac{1}{2}m\ v \omega^2\ A^2](https://tex.z-dn.net/?f=P%20%3D%20%5Cdfrac%7B1%7D%7B2%7Dm%5C%20v%20%5Comega%5E2%5C%20A%5E2)
![P = \dfrac{1}{2}\times 0.00331\times 105.84\times 743^2\ 0.0022^2](https://tex.z-dn.net/?f=P%20%3D%20%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%200.00331%5Ctimes%20105.84%5Ctimes%20743%5E2%5C%200.0022%5E2)
P = 0.438 W
Answer: 148348.6239 kg•m/s
Explanation: Firstly, we need to convert the 14700 N into kilograms, and to do so, use the formula net force is equal to mass times acceleration and rearrange the formula to find mass like shown below...
F = ma
F/a = m
14700/9.81 = 1498.470948 kg, this is your mass
Now that we convert it into kilograms, plug all the numbers into the variable of the momentum formula.
Momentum formula is P = mass x velocity
Like this:
P = 1498.470948 x 99
p = 148348.6239 kg•m/s.
I believe that is your answer, hope that helps you even a bit out.
Thanks.