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3 years ago

8. If a circuit has a current of 25.4 amps with 12.6

Physics

1 answer:

grin007 [14]3 years ago

8 0

The resistance of the circuit is $0.496 \Omega$

Explanation:

We can solve the problem by applying Ohm's law, which gives us the relationship between current, potential difference and resistance in a circuit:

$V=RI$

where

V is the potential difference

R is the resistance

I is the current

For the circuit in this problem,

V = 12.6 V

I = 25.4 A

Re-arranging the equation, we can solve for the resistance:

$R=\frac{V}{I}=\frac{12.6}{25.4}=0.496 \Omega$

Learn more about current and potential difference here:

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A weight of 1400 pounds is suspended from two cables as shown in the figure. What is the tension in the left cable? _________ po

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Answer:

Following are the solution to this question:

Explanation:

Law:

$\to \theta= 180^{\circ}- 50^{\circ}- 25^{\circ}$

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$\to T_L=931.65 \ pounds \\\\ \to T_R=1313.59 \ pounds \\\\$

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2 years ago

A 5.6 g marble is fired vertically upward using a spring gun. The spring must be compressed 6.4 cm if the marble is to just reac

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2 years ago

A 6.3 g bullet leaves the muzzle of a rifle with a speed of 596.2 m/s. what constant force is exerted on the bullet while it is

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anwser will be

F = ma

where

F = force exerted on the bullet
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Substituting appropriately,

F = 0.005a --- call this Equation 1

Next working equation is

Vf^2 - Vo^2 = 2as

where

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s = length of the rifle's barrel

Substituting appropriately,

326^2 - 0 = 2(a)(0.83)

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the anwser will be
Substituting this into Equation 1,

F = 0.005(64,022)

F =320.11 Newtons

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3 years ago

A hungry lion is looking for food. It went 5 miles (mi) before it spotted a zebra to stalk. It took this lion 0.2 hours to get t

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3 years ago

Read 2 more answers

An elevator cab and its load have a combined mass of 1600 kg. Find the tension in the supporting cable when the cab, originally

amid [387]

The tension in the supporting cable when the cab originally moves downward is 18422.4 N

What is tension?

Tension is described as the pulling force by the means of a three-dimensional object.

Tension might also be described as the action-reaction pair of forces acting at each end of said elements.

Here,

m =combined mass = 1600 kg

s = Displacement of the elevator = 42 m

g = Acceleration due to gravity = 9.81 m/s²

u = Initial velocity = 12 m/s

v = Final velocity = 0

According to the equation of motion:

$v^{2} - u^{2} = 2as$

0 - 12^2 = 2*a*42

a = - 144 / 84

a = - 1.714 m/s^2

Now let's write the equation of the forces acting on the elevator. Taking upward as positive direction:

T-mg = ma

T = m(g-a)

T = 1600 ( 9.8-(-1.74))

T=18422.4 N

Hence,

The tension in the supporting cable when the cab, originally moving downward is 18422.4 N

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1 year ago