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neonofarm [45]
3 years ago
14

Which of the following would describe a length that is 2.0×10^-3 of a meter? a: 2.0 kilometers

Physics
1 answer:
natita [175]3 years ago
5 0

Answer:

Option (c) 2\times 10^{-3}\ m=2\ millimeters

Explanation:

Here, it is required to describe the given length in a particular unit. Firstly, we need to see the following conversions as :

1 meter = 0.001 kilometers

1 meter = 10⁻⁶ megameters

1 meter = 1000 millimeters

1 meter = 1000000 micrometers

From the given option, the correct one is (c) because, 1 meter = 1000 millimeters

So, 2\times 10^{-3}\ m=2\ millimeters

Hence, the correct option is (c). Hence, this is the required solution.

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A 0.0382-kg bullet is fired horizontally into a 3.78-kg wooden block attached to one end of a massless, horizontal spring (k = 8
wel

Answer:

280.87 ms⁻¹

Explanation:

Consider the motion of the bullet-block combination after collision

m = mass of the bullet = 0.0382 kg

M = mass of wooden block = 3.78 kg

V = velocity of the bullet-block combination after collision

k = spring constant of the spring = 833 N m⁻¹

A = Amplitude of oscillation = 0.190 m

Using conservation of energy

Kinetic energy of  bullet-block combination after collision = Spring potential energy gained due to compression of spring

(0.5)(m + M)V^{2} = (0.5)kA^{2}

(0.0382 + 3.78)V^{2} = (833)(0.190)^{2}

V = 2.81 ms⁻¹

v_{o} = initial velocity of the bullet before striking the block

Using conservation of momentum for the collision between bullet and block

m v_{o} = (m + M) V

(0.0382) v_{o} = (0.0382 + 3.78) (2.81)

v_{o} = 280.87 ms⁻¹

7 0
3 years ago
Why do the lighter isotopes disappear first from the atmosphere? Where do those isotopes go?
denpristay [2]

Lighter molecules move fast and escape from the upper atmosphere relatively quickly.

To find the answer, we have to know more about the lighter isotopes.

<h3>What are lighter isotopes?</h3>
  • Lighter molecules are mobile and soon leave the higher atmosphere.
  • A particular element's stable isotopes have slightly different atomic masses and quantum mechanical energies.
  • The lighter isotope of an element's chemical bonds are more easily broken than the heavier isotope's.
  • As a result, the light isotope typically benefits from chemical reactions.

Thus, we can conclude that, lighter molecules move fast and escape from the upper atmosphere relatively quickly.

Learn more about the isotopes here:

brainly.com/question/364529

#SPJ4

3 0
2 years ago
You are walking from your math class to your science class. You are carrying books
kolezko [41]

Answer:

1800J

Explanation:

Given parameters:

Weight of the book  = 20N

Total distance covered  = 45m + 15m + 30m  = 90m

Unknown:

Total work performed on the books  = ?

Solution:

To solve this problem we must understand that work done is the force applied to move a body through a certain distance.

So;

    Work done  = Force x distance

  Work done  = 20 x 90  = 1800J

8 0
3 years ago
Find the position of the center of mass of the system of the sun and Jupiter? (Since Jupiter is more massive than the rest of th
8090 [49]

Answer:

r_{cm} = 0.074 m from the position of the center of the Sun

Explanation:

As we know that mass of Sun and Jupiter is given as

M_s = 1.98 \times 10^{30} kg

M_j = 1.89 \times 10^{27} kg

distance between Sun and Jupiter is given as

r = 7.78 \times 10^{11} m

now let the position of Sun is origin and position of Jupiter is given at the position same as the distance between them

so we will have

r_{cm} = \frac{M_s r_1 + M_j r_2}{M_s + M_j}

r_{cm} = \frac{1.98 \times 10^{30} (0) + (1.89 \times 10^{27})(7.78 \times 10^{11})}{1.98 \times 10^{30} + 1.89 \times 10^{27}}

r_{cm} = 0.074 m from the position of the center of the Sun

3 0
4 years ago
What happens to the force between two charges if one of the charges are doubled?
Julli [10]

Answer:

The new force between the charges becomes double of the initial force.

Explanation:

The force acting between charge particles is given by :

F=k\dfrac{q_1q_2}{r^2}

k is electrostatic constant

r is distance between charges

If one of the charges are doubled, then, q₁ = 2q₁

The new force becomes,

F'=\dfrac{2kq_1q_2}{r^2}\\\\F'=2F

So, the new force between the charges becomes double of the initial force.

7 0
4 years ago
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