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sveticcg [70]
3 years ago
14

Finding spring constant given displacement of spring and distance traveled by a cart

Physics
1 answer:
Alborosie3 years ago
5 0
 - (spring constant) (new length of spring - original length of spring) = Force applied to spring.
that is
-kx=F

Did you only have how far the cart traveled? No mass or acceleration or speed or time taken?
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Can spoon ring like a bell prove it
mote1985 [20]
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A sound is produced because the spoon vibrated, causing sound waves to travel up the string and into ears.
4 0
3 years ago
1.Explain frame of reference. How is it different when you are riding inside a car or standing by the highway?
galben [10]

Answer:

See explanation

Explanation:

A frame of reference simply refers to a set of coordinates which is used to determine the position and velocity of objects all the objects found in that particular frame. The person inside the car and standing by the highway are in different frames of reference.

Newtons first law of motion states that an object will continue to be at rest or in a state of uniform velocity until it is acted upon by an external force.

Newtons second law states that rate of change of momentum is directly proportional to the impressed force.

Newtons third law states that action and reaction are equal and opposite.

The action of applying brakes leads to an equal reaction of a sudden forward movement. Seat belts help to prevent the occupants of a car from being injured by the sudden stoppage of the car.

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strong nuclear force, electromagnetic force, weak nuclear force and gravity

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8 0
3 years ago
. A dog walks 14 m to the east and then 20 m back to the west. What is the distance? What is the displacement?​
Crank

Answer:

Hi...

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3 0
3 years ago
To ancient peoples, why were planets special?
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Answer:

Planets were like gods.

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7 0
3 years ago
A 600g toy train completes 10 laps of its circular track in 1 min 20s. If the radius of the track is 1.2 m, Find the centripetal
Lynna [10]

Wow !  This will take more than one step, and we'll need to be careful
not to trip over our shoe laces while we're stepping through the problem.

The centripetal acceleration of any object moving in a circle is

                          (speed-squared)  /  (radius of the circle)  .

Notice that we won't need to use the mass of the train.

We know the radius of the track.  We don't know the trains speed yet,
but we do have enough information to figure it out.  That's what we
need to do first.

Speed  =  (distance traveled) / (time to travel the distance).

Distance = 10 laps of the track.   Well how far is that ? ? ?

1 lap = circumference of the track = (2π) x (radius) =  2.4π  meters

10 laps =  24π  meters.

Time = 1 minute 20 seconds  =  80 seconds

The trains speed is  (distance) / (time)

                               =  (24π meters) / (80 seconds)

                               =        0.3 π  meters/second .

NOW ... finally, we're ready to find the centripetal acceleration.

                                 <span> (speed)²  /  (radius)

                           =    (0.3π m/s)²  /  (1.2 meters)

                           =    (0.09π m²/s²)  /  (1.2 meters)

                           =    (0.09π  /  1.2)   m/s²

                           =          0.236  m/s²  .        (rounded)

If there's another part of the problem that wants you to find
the centripetal FORCE ...

Well,       Force = (mass) · (acceleration) .

We know the mass, and we ( I ) just figured out the acceleration,
so you'll have no trouble calculating the centripetal force.       </span>
4 0
3 years ago
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