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Alexus [3.1K]
3 years ago
15

[10 POINTS ❗️❗️ and brainlist :)]

Physics
2 answers:
ludmilkaskok [199]3 years ago
6 0
The answer to this is D
a_sh-v [17]3 years ago
4 0

Answer:

D) Strong gravitational force of the earth

Explanation:

Gravitational force is the force that attracts to objects with mass.This forces tries to pull masses together, that is why attractive in nature.

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Graphs help you see..
Diano4ka-milaya [45]
I think it's B because when you graph you do see the relationship between the dependent and independent variable
8 0
3 years ago
William made one comment to an employee recently assigned to his team complimenting her on her dress. Later she was reprimanded
Ilya [14]

Answer:

C

Explanation:

William should fully in the investigation. If the only plausible evidence of sexual harassment  is a subtle compliment of an employee's choice or way of dressing. Such comments may be opinionated but are insufficient or a weak evidence for a sexual harassment case.    

5 0
2 years ago
Read 2 more answers
Heat transfer between two substances is affected by specific heat and the
Pie
<span>Heat transfer between two substances is affected by specific heat and the "Temperature difference between them"

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6 0
3 years ago
Read 2 more answers
A copper cylinder is initially at 21.1 ∘C . At what temperature will its volume be 0.163 % larger than it is at 21.1 ∘C?
fomenos

To solve this problem we will apply the concepts related to the final volume of a body after undergoing a thermal expansion. To determine the temperature, we will use the given relationship as well as the theoretical value of the volumetric coefficient of thermal expansion of copper. This is, for example to the initial volume defined as V_1, the relation with the final volume as

V_2 = V_1 +0.163\% V_1

V_2 = V_1 +0.00163V_1

V_2 = 1.00163V_1

Initial temperature = 21.1\°C

Let T be the temperature after expanding by the formula of volume expansion

we have,

V_2 = V_1 (1+\gamma \Delta t)

Where \gamma is the volume coefficient of copper 5.1*10^{-5}/C

1.00163V_1 = V_1(1+\gamma(T-21.1\°))

1.00163 = 1+5.1*10^{-5}(T-21.1\°)

0.00163 = 0.000051T-0.0010761

T = 53.0608\°C

Therefore the temperature is 53.06°C

7 0
3 years ago
Calculate the work done by an applied force of 76.0 N on a crate for the following. (Include the sign of the value in your answe
telo118 [61]

Answer:

a) 400.4Joules

b) 262.69Joules

Explanation:

Work is said to be done if the force applied to an object cause the object to move through a distance

Workdone = Force × Distance

Given

Force = 76N

Distance= 5.2m

Work done = 77 × 5.2

Work done = 400.4Joules

b) If the force is exerted at an angle of 41°

Work done = Fdsin theta

Work done = 77(5.2)sin41

Work done = 400.4sin41

Work done = 262.69Joules

6 0
3 years ago
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