<span>Answer: 6.1 g of Ca(NO₃)₂•4H₂O and 5.5 g of KIO₃
</span>
<span>Explanation:
</span>
1) Calculate the number of moles of <span>Ca(NO₃)₂ in 10.0 g
</span>
i) molar mass of <span>Ca(NO₃)₂ = 40.1 g/mol + 2x126.9 g/mol + 2x3x16.0 g/mol = 389.9 g/mol
</span>
<span>ii) Formula: number of moles = mass in grams / molar mass
</span>number of moles = 10.0 g / 389.9 g/mol = 0.02565 moles of Ca(NO₃)₂
<span>
</span><span>2) Write the chemical equation to state the mole ratio:</span>
<span />
<span>i) Ca(NO₃)2•4H₂O(s) + 2KIO₃(s) --> Ca(IO₃)₂(s) + 2KNO₃ + 4H₂O
</span>
ii) mole ratio: 1 mol Ca(NO₃)2•4H₂O(s) : 2 mol KIO₃(s) : 1 mol <span>Ca(IO₃)₂(s)
</span>
3) Use proportionality to find the actual number of moles
<span>
</span><span>i) </span>Ca(NO₃)₂•4H₂O(s)
1 mol <span>Ca(NO₃)₂•4H₂O(s) / 1 mol Ca(IO₃)₂ = x / 0.02565 mol Ca(IO₃)₂ => x = 0.02565 mol </span>Ca(NO₃)₂•4H₂O(s)
molar mass of <span><span>Ca(NO₃)₂•4H₂O(s)</span> = 40.0g/mol + 2x14.0g/mol + 2x3x16.0g/mol + 4x18.0g/mol = 236.0g/mol
</span>
<span>mass in grams = number of moles x molar mass = 0.02565 mol x 236.0 g/mol = 6.1 g
</span>ii) KIO₃
<span />
<span>1mol KIO₃/1molCa(IO₃)₂ = x / 0.02565 mol Ca(IO₃)₂ => x = 0.02565 mol KIO₃</span>
<span>molar mas of KIO₃ = 39.1 g/mol + 126.9 g/mol + 3x16.0 g/mol = 214.0 g/mol
</span>
mass in grams = 0.02565 mol x 214.0 g/mol = 5.5 g
That is, water has a high heat of vaporization, the amount of energy needed to change one gram of a liquid substance to a gas at constant temperature. Water's heat of vaporization is around 540 cal/g at 100 °C, water's boiling point.
Density, Volume and Mass
3. A metal weighing 7.101 g is placed in a graduated cylinder containing 33.0 mL of water. The water
level rose to the 37.4 mL mark.
a) Calculate the density of the metal (in g/mL).
b) If you were to do this with an equal mass of aluminum (d = 2.7 g/mL), how high would the water rise?
Answer is: <span>3 particles would one formula unit of CaCl</span>₂<span> produce when dissolved in solution.
Chemical reaction of calcium chloride dissolving in water:
CaCl</span>₂(aq) → Ca²⁺(aq) + 2Cl⁻(aq).
<span>There are one calcium cation and two chlorine anions in solution from one formula unit of calcium chloride.</span>
.0000015 meters squared. just got to move the decimal