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3 years ago

Please help me!!!!

Chemistry

1 answer:

Tems11 [23]3 years ago

3 0

Answer:

1. They will react.

2. 2HCI + Zn —> ZnCl2 + H2

Explanation:

1. From the question given above,

We can see that Zn is higher than H in the activity series.

NOTE: Elements higher (i.e at the top) in the activity series will displace those lower (i.e at the bottom) in the series. Thus, Zn is higher in the series than H. Therefore, Zn will displace H from solution. Hence, they will react.

2. The product obtained from the reaction can be seen as follow:

HCI + Zn —> ZnCl2 + H2

The above equation can be balance as follow:

There are 2 atoms of H on the right side and 1 atom on the left side. It can be balance by putting 2 in front of HCl as shown below:

2HCI + Zn —> ZnCl2 + H2

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2 years ago

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<h2>Lead(II) oxide</h2>

Explanation:

<h3>Lead(II) oxide, also called lead monoxide, is the inorganic compound with the molecular formula PbO. PbO occurs in two polymorphs: litharge having a tetragonal crystal structure, and massicot having an orthorhombic crystal structure. Modern applications for PbO are mostly in lead-based industrial glass and industrial ceramics, including computer components. It is an amphoteric oxide.[3]</h3>

IUPAC name
Lead(II) oxide

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pls brainlest meh

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2 years ago

For the reaction, calculate how many grams of the product form when 14.4 g of Br2 completely reacts. Assume that there is more t

lora16 [44]

Answer:

The answer to your question is 21.45 g of KBr

Explanation:

Chemical reaction

2K + Br₂ ⇒ 2KBr

14.4 ?

Process

1.- Calculate the molecular mass of bromine and potassium bromide

Bromine = 2 x 79.9 = 159.8g

Potassium bromide = 2(79.9 + 39.1) = 238 g

2.- Solve it using proportions

159.8 g of Bromine ------------ 238 g of potassium bromide

14.4 g of Bromine ------------ x

x = (14.4 x 238) / 159.8

x = 3427.2 / 159.8

x = 21.45g of KBr

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4 years ago