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3 years ago

A graph of energy consumption in the United States versus time slopes upward. This indicates that energy consumption has _____ .

Chemistry

2 answers:

vredina [299]3 years ago

5 0

Answer: Option (a) is the correct answer.

Explanation:

The graph shows that as and when time increases the need for energy consumption also increases.

This might be due to increase in population with time that has lead to increase in consumption of energy.

Thus, we can conclude that out of the given options, a graph of energy consumption in the United States versus time slopes upward. This indicates that energy consumption has increased.

galben [10]3 years ago

4 0

Answer: I looked it up and so the answer is A. I am 100% sure

Have a nice day and I hope this helps! :)

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Carbon dioxide emissions will____in the next century and global temperatures will ____.

Vesna [10]

Carbon dioxide emissions will grow in the next century and global temperatures will increase.

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3 years ago

How many moles of elemental oxygen gas (o2) must react with elemental chlorine (cl2) to produce 60.7 moles of dichlorine heptoxi

Dafna11 [192]

The balanced chemical reaction that would occur here would be:
7O2 + 2 Cl2 --> 2 Cl2O7
To determine the moles of oxygen that is needed in the system, we use the given amount of the product that is needed to be produced. Then, we use the relation from the balanced reaction to relate the product and one of the reactants. We do as follows:

moles Cl2O7 = 60.7 mol

moles O2 = 60.7 mol Cl2O7 ( 7 mol O2 / 2 mol Cl2O7 )
moles O2 = 212.45 mol O2

Therefore, about 213 moles of oxygen gas is needed in order to producr 60.7 moles of dichlorine heptoxide.

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4 years ago

What kind of weather can Wyoming soon expect?

dezoksy [38]

Answer:

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Explanation:idk if this helps awnser ur question

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3 years ago

Help me plzz and thank u

Gennadij [26K]

Answer:

the terminator because i did this test

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3 years ago

Calculate how many grams of sodium azide (NaN3) are needed to inflate a 25.0 × 25.0 × 20.0 cm bag to a pressure of 1.35 atm at a

Luden [163]

Answer : The mass of $NaN_3$ at temperature $20^oC$ 28.47 g.

The mass of $NaN_3$ at temperature $10^oC$ 29.51 g.

Solution : Given,

Pressure of gas = 1.35 atm

Temperature of gas = $20^oC=273+20=293K$ $(0^oC=273K)$

Volume of gas = $25\times 25\times 20cm=12500cm^3=12.5L$ $(1L=1000cm^3)$

Molar mass of $NaN_3$ = 65 g/mole

Part 1 : First we have to calculate the moles of gas at temperature $20^oC$ . The gas produced in the given reaction is $N_2$ .

Using ideal gas equation,

$PV=nRT$

where,

P = pressure of the gas

V = volume of the gas

T = temperature of the gas

n = number of moles of gas

R = Gas constant = 0.0821 Latm/moleK

Now put all the given values in this formula, we get

$(1.35atm)\times (12.5L)=n\times (0.0821Latm/moleK)\times (293K)$

By rearranging the terms, we get the value of 'n'

$n=0.7015moles$

The moles of $N_2$ = 0.7015 moles

The given balanced reaction is,

$20NaN_3(s)+6SiO_2(s)+4KNO_3(s)\rightarrow 32N_2(g)+5Na_4SiO_4(s)+K_4SiO_4(s)$

As, 32 moles of $N_2$ produced from 20 moles of $NaN_3$

So, 0.7015 moles of $N_2$ produced from $\frac{20}{32}\times 0.7015=0.438$ moles of $NaN_3$

Now we have to calculate the mass of $NaN_3$ .

$\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3$

$\text{ Mass of }NaN_3=(0.438moles)\times (65g/mole)=28.47g$

Therefore, the mass of $NaN_3$ needed are 28.47 g.

Part 2 : We have to calculate the moles of gas at temperature $10^oC$ and same volume & pressure.

Using ideal gas equation,

$PV=nRT$

Now put all the given values in this formula, we get

$(1.35atm)\times (12.5L)=n\times (0.0821Latm/moleK)\times (283K)$

By rearranging the terms, we get the value of 'n'

$n=0.726moles$

The moles of $N_2$ = 0.726 moles

The given balanced reaction is,

$20NaN_3(s)+6SiO_2(s)+4KNO_3(s)\rightarrow 32N_2(g)+5Na_4SiO_4(s)+K_4SiO_4(s)$

As, 32 moles of $N_2$ produced from 20 moles of $NaN_3$

So, 0.726 moles of $N_2$ produced from $\frac{20}{32}\times 0.726=0.454$ moles of $NaN_3$

Now we have to calculate the mass of $NaN_3$ .

$\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3$

$\text{ Mass of }NaN_3=(0.454moles)\times (65g/mole)=29.51g$

Therefore, the mass of $NaN_3$ needed are 29.51 g.

7 0

4 years ago