Answer:
The value of impulse of the net force on the ball during its collision with wall is
The value of average horizontal force that the wall exerts on the ball during the impact is F = 15000 N
Explanation:
Mass of the ball = 0.5 kg
Horizontal velocity = 20
Velocity after collision = - 10
(A). Impulse of the net force on the ball during its collision with wall is
I = 0.5 × (20 + 10)
This is the value of impulse of the net force on the ball during its collision with wall.
(B). The magnitude of average horizontal force
Where F = Force
I = impulse & t = time interval = 0.001 sec
F = 15000 N
This is the value of average horizontal force that the wall exerts on the ball during the impact.
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