Answer:
true
Explanation:
the wavelength of AM radio is 10 m whereas FM has 1 m
We can use the formula of the moment of inertia given by:
![r\cdot F=I\alpha](https://tex.z-dn.net/?f=r%5Ccdot%20F%3DI%5Calpha)
Where:
r = Distance from the point about which the torque is being measured to the point where the force is applied
F = Force
I = Moment of inertia
α = Angular acceleration
So:
![\begin{gathered} r\cdot F=(-0.26\times314+290\times0.32)=92.8-81.64=11.16 \\ I=0.930 \\ so,_{\text{ }}solve_{\text{ }}for_{\text{ }}\alpha: \\ \alpha=\frac{r\cdot F}{I} \\ \alpha=\frac{11.16}{0.930} \\ \alpha=\frac{12rad}{s^2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20r%5Ccdot%20F%3D%28-0.26%5Ctimes314%2B290%5Ctimes0.32%29%3D92.8-81.64%3D11.16%20%5C%5C%20I%3D0.930%20%5C%5C%20so%2C_%7B%5Ctext%7B%20%7D%7Dsolve_%7B%5Ctext%7B%20%7D%7Dfor_%7B%5Ctext%7B%20%7D%7D%5Calpha%3A%20%5C%5C%20%5Calpha%3D%5Cfrac%7Br%5Ccdot%20F%7D%7BI%7D%20%5C%5C%20%5Calpha%3D%5Cfrac%7B11.16%7D%7B0.930%7D%20%5C%5C%20%5Calpha%3D%5Cfrac%7B12rad%7D%7Bs%5E2%7D%20%5Cend%7Bgathered%7D)
Answer:
12 rad/s²
Answer:
Bcuz when solid is near heat it changes to liquid this is called physical change
Work done = force × distance travelled in the direction of the force
Force= 2(9.81) = 19.62N
WD= 19.62×130= 2550.6Nm
Answer:
d. 0V
Explanation:
The magnitude of four point charges are +3q, -q, +2q and -4q. I think you forget to mention the signs.
As we know that the potential due to the point charge that has traveled the distance d can be represented mathematically as,
![V = k\frac{q}{r}](https://tex.z-dn.net/?f=V%20%3D%20k%5Cfrac%7Bq%7D%7Br%7D)
= 1/4λε = 9×
Nm²/C²
Now as it is mentioned in the question that all four charges are arranged in the corners of a square so there distance from the center is same. We can rewrite the above potential equation as follows.
(1)
We can find out d by the pythagoras theorem, as we are dealing with square so d is a semi diagonal.
![d = \sqrt{\frac{L^{2} }{4}+\frac{L^{2} }{4} } = \frac{\sqrt{2} }{2} L](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%5Cfrac%7BL%5E%7B2%7D%20%7D%7B4%7D%2B%5Cfrac%7BL%5E%7B2%7D%20%7D%7B4%7D%20%20%7D%20%3D%20%5Cfrac%7B%5Csqrt%7B2%7D%20%7D%7B2%7D%20L)
by putting all values in equation (1)
V = ![\frac{9*10^{9} }{\frac{\sqrt{2} }{2} L } (+3q-q+2q-4q)](https://tex.z-dn.net/?f=%5Cfrac%7B9%2A10%5E%7B9%7D%20%7D%7B%5Cfrac%7B%5Csqrt%7B2%7D%20%7D%7B2%7D%20L%20%7D%20%28%2B3q-q%2B2q-4q%29)
V = 0V