1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sedbober [7]
3 years ago
12

Two strong permanent magnets are placed one inch apart. Which two fundamental forces will most affect them?

Physics
1 answer:
Anuta_ua [19.1K]3 years ago
3 0
The answer i got was c. gravity and strong
i hope it helps

You might be interested in
Choose one of these three people and write a letter to them to express your concerns about the events of 01/06/21
Mashcka [7]
Bro I didn’t put nothing
6 0
2 years ago
A tennis ball with mass m travelling west,hits a wall with a velocity of v.It bounces back with a velocity 1 ,63 v an easterly d
Pepsi [2]

Answer:

163 v an easterly direction

6 0
3 years ago
A thin nonconducting rod with a uniform distribution of positive charge Q is bent into a complete circle of radius R. The centra
Dmitriy789 [7]

Answer:

(a). If z = 0, The electric field due to the rod is zero.

(b). If z =  ∞, The electric field due to the rod is E\propto\dfrac{1}{z^2}.

(c). The positive distance is \dfrac{R}{\sqrt{2}}

(d). The maximum magnitude of electric field is 1.54\times10^{4}\ N/C

Explanation:

Given that,

Radius = 2.00 cm

Charge = 4.00 mC

(a). If the radius and charge are R and Q.

We need to calculate the electric field due to the rod

Using formula of electric field

E=\dfrac{1}{4\pi\epsilon_{0}}\dfrac{Qz}{(z^2+R^2)^{\frac{2}{3}}}

Where, Q = charge

z = distance

If z = 0,

Then, The electric field is

E=0

(b). If z = ∞, z>>R

So, R = 0

Then, the electric field is

E=\dfrac{1}{4\pi\epsilon_{0}}\dfrac{Q}{z^2}

E\propto\dfrac{1}{z^2}

(c). In terms of R,

We need to calculate the positive distance

If E\rightarrow E_{max}

Then, \dfrac{dE}{dz}=0

\dfrac{Q}{4\pi\epsilon_{0}}(\dfrac{(z^2+R^2)^\frac{3}{2}-\dfrac{3z}{2}(z^2+R^2)^\dfrac{1}{2}}{(z^2+R^2)^2})=0

Taking only positive distance

z=\dfrac{R}{\sqrt{2}}

(d). If R = 2.00 and Q = 4.00 mC

We need to calculate the maximum magnitude of electric field

Using formula of electric field

E_{max}=\dfrac{1}{4\pi\epsilon_{0}}\dfrac{Qz}{(z^2+R^2)^{\frac{2}{3}}}

E_{max}=9\times10^{9}\times\dfrac{4.0\times10^{-6}\times\dfrac{2.00}{\sqrt{2}}}{((\dfrac{2.00}{\sqrt{2}})^2+(2.00)^2)^{\frac{2}{3}}}

E_{max}=15418.7\ N/C

E_{max}=1.54\times10^{4}\ N/C

Hence, (a). If z = 0, The electric field due to the rod is zero.

(b). If z =  ∞, The electric field due to the rod is E\propto\dfrac{1}{z^2}.

(c). The positive distance is \dfrac{R}{\sqrt{2}}

(d). The maximum magnitude of electric field is 1.54\times10^{4}\ N/C

6 0
2 years ago
The 68-kg crate is stationary when the force P is applied. Determine the resulting acceleration of the crate if (a) P = 0, (b) P
bogdanovich [222]

Explanation:

Mass of the crate, m = 68 kg

We need to find the resulting acceleration if :

(a) Force, P = 0

P = m a

⇒ a = 0

(b) P = 181 N

a=\dfrac{P}{m}

a=\dfrac{181\ N}{68\ kg}

a=2.67\ m/s^2

(c) P = 352 N

a=\dfrac{P}{m}

a=\dfrac{352\ N}{68\ kg}

a=5.17\ m/s^2

Hence, this is the required solution.

5 0
3 years ago
What is the part of the cell that controls all the other parts?
Harrizon [31]
A nucleus controls all the other parts of the cell
3 0
3 years ago
Other questions:
  • To maintain a constant speed, the force provided by a car's engine must equal the drag force plus the force of friction of the r
    10·1 answer
  • Which of the following is a good electrical conductor?
    9·1 answer
  • What is the volume occupied at stp by a mixture of 4.00 g of he(g),?
    8·1 answer
  • If "38 %" of the light passes through this combination of filters, what is the angle between the transmission axes of the filter
    5·1 answer
  • All of the following are basic need of young children, except
    12·2 answers
  • 2. Calculate the work done by a 57 N force pushing a 0.025 kg pencil 0.25 m against a force of 23 N.​
    15·1 answer
  • If a 140 lb. climber saved her potential energy as she descended from Mt. Everest (Elev. 29,029 ft) to Kathmandu (Elev. 4,600 ft
    5·1 answer
  • PLS HELP FOR PHYSICS
    15·2 answers
  • Plzzz answer this correctly
    5·1 answer
  • Calculate the Work done if the force is 2000 Newtons<br> and the distance is 5 km.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!