AB and AB’ are congruent
BC and B’C are congruent
All angles are congruent to the original angles
2,830 x 3 =G three times 0 is 0
2,830 3 times 3 is 9
x 3 3 times 8 is 24 carry the two
8,490 3 times 2 is 6 plus the carried 2 is 8
The first interception for this function would be at (1,0) the next would be (4,0)
Answer:
<h3>11.8 feet</h3>
Step-by-step explanation:
Given
Length of the ladder = 12foot
angle of elevation = 80 degrees
Required
Height of the wall (opposite side)
The set up will form a right angled triangle where
length of the ladder is the hypotenuse
height of the wall is opposite;
Using SOH, CAH, TOA trig identity
According to SOH
sin 80 = opp/hyp
sin80 = opp/12
opp = 12sin80
opp = 11.82 feet
Hence the height of the wall is 11.8feet (to the nearest tenth)
Answer:
5507.79 feet
Step-by-step explanation:
To find the height of the mountain, we can draw triangles as in the image attached.
Let's call the height of the mountain 'h', and the distance from the first point (31 degrees) to the mountain 'x'.
Then, we can use the tangent relation of the angles:
tan(34) = h/x
tan(31) = h/(x+1000)
tan(31) is equal to 0.6009, and tan(34) is equal to 0.6745, so:
h/x = 0.6745 -> x = h/0.6745
using this value of x in the second equation:
h/(x+1000) = 0.6009
h/(h/0.6745 + 1000) = 0.6009
h = 0.6009 * (h/0.6745 + 1000)
h = 0.8909*h + 600.9
0.1091h = 600.9
h = 600.9 / 0.1091 = 5507.79 feet