6.0 is the answer. hope this helps ya
To solve this problem, it is necessary to apply the concepts related to force described in Newton's second law, so that
F = ma
Where,
m = mass
a = Acceleration (Gravitational acceleration when there is action over the object of the earth)
Torque, as we know, is the force applied at a certain distance, that is,

Where
F= Force
d = Distance
Our values are given as,



Since the system is in equilibrium the difference of the torques is the result of the total Torque applied, that is to say






Therefore the magnitude of the frictional torque at the axle of the pulley if the system remains at rest when the balls are released is 
Answer: 25.7m/s
Explanation: the cars have equal masses so we only consider their velocities,
The cars traveled together at 65° north of east this is with a velocity equal to the resultant velocity,
Using the force diagram as shown below;
Tan 65° = Vn/Ve
Ve is velocity of the car traveling east
Vn is velocity of car traveling north
Tan 65° = V2/12
2.144 = V2/12
V2 = 12 * 2.144
V2 = 25.7 m/s