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hammer [34]
3 years ago
13

Which shows all the equations that represent

Mathematics
2 answers:
olchik [2.2K]3 years ago
6 0

Answer:

c

Step-by-step explanation:

Arturiano [62]3 years ago
5 0

Answer:

the answer is H because it is h

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How do you find the value of 2 X 10 to the 3rd power don't know how to write an exponent on computer?
blagie [28]
I'm assuming that the number ten is to the third power.
2 x (10 x 10 x 10) = 2 x (1000)

Answer=2000
7 0
4 years ago
Help plzzz question 18
kolezko [41]
B can be either 6 or 4

6 0
4 years ago
Some number plus – 49 is equal to the number divided by 4.
Komok [63]

Answer:

X+(-49)=X/4

Step-by-step explanation:

A number represented by X

plus negative forty-nine

is equal to the number (X) divided by 4

3 0
3 years ago
X is 21 more than 21
Alenkinab [10]
X +21 > 21
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6 0
4 years ago
Read 2 more answers
Suppose r(t) = (et cos t)i + (et sin t)j. Show that the angle between r and a never changes. What is the angle?
tatyana61 [14]

Answer:

Angle = Ф = cos^{-1}(0) = 0

Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.

Step-by-step explanation:

Given vector r(t) = e^{t}cost i + e^{t}sint j

As we know that,

velocity vector = v = \frac{dr}{dt}

Implies that

velocity vector = (e^{t} cost - e^{t} sint)i + (e^{t} sint - e^{t}cost )j

As acceleration is velocity over time so:

acceleration vector = a = \frac{dv}{dt}

Implies that

vector a =

(e^{t}cost - e^{t}sint - e^{t}sint - e^{t}cost )i + ( e^{t}sint + e^{t}cost + e^{t}cost - e^{t}sint )j

vector a = (-2e^{t}sint) i + ( 2e^{t}cost)j

Now scalar product of position vector r and acceleration vector a:

r. a = . \\

r.a = -2e^{2t}sintcost + 2e^{2t}sintcost

r.a = 0

Now, for angle between position vector r and acceleration vector a is given by:

cosФ = \frac{r.a}{|r|.|a|} = \frac{0}{|r|.|a|} = 0

Ф = cos^{-1}(0) = 0

Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.

4 0
3 years ago
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