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Scrat [10]
3 years ago
9

A population of insects grows exponentially, as shown in the table. Suppose the increase in population continues at the same rat

e.
What is the insect population at the end of week 11?

Round to the nearest whole number.

Mathematics
1 answer:
Yuki888 [10]3 years ago
5 0

A population of insects grows exponentially, as shown in the table. Suppose the increase in population continues at the same rate.

from the given table

when x=0 , y=20

when x= 1 , y = 30

We use this information to find exponential growth equation

General form of exponential growth is

y=a(b)^x

WE plug in the given values and find out value of a  and b

when x=0 , y=20

20=a(b)^0

20 = a

Now we find out b

when x= 1 , y = 30

30=20(b)^1

divide both sides by 20

\frac{3}{2} = b

So exponential function becomes

y=20(\frac{3}{2})^x

Now we find the insect population at the end of week 11

We plug in 11 for x

y=20(\frac{3}{2})^x

y=20(\frac{3}{2})^11= 1729.951171875

Round the answer to nearest whole number

1730 is the insect population at the end of week 11

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Answer:

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If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

\displaystyle \int \dfrac{12}{1-\sin (6x)}\:\:\text{d}x

\boxed{\begin{minipage}{5 cm}\underline{Terms multiplied by constants}\\\\$\displaystyle \int a\:\text{f}(x)\:\text{d}x=a \int \text{f}(x) \:\text{d}x$\end{minipage}}

If the terms are multiplied by constants, take them outside the integral:

\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)}\:\:\text{d}x

Multiply by the conjugate of 1 - sin(6x) :

\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)} \cdot \dfrac{1+\sin(6x)}{1+\sin(6x)}\:\:\text{d}x

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\textsf{Use the identity} \quad \sin^2 x+ \cos^2 x=1:

\implies \sin^2 (6x) + \cos^2 (6x)=1

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Expand:

\implies 12\displaystyle \int \dfrac{1}{\cos^2(6x)}+\dfrac{\sin(6x)}{\cos^2(6x)} \:\:\text{d}x

\textsf{Use the identities }\:\: \sec \theta=\dfrac{1}{\cos \theta} \textsf{ and } \tan\theta=\dfrac{\sin \theta}{\cos \theta}:

\implies 12\displaystyle \int \sec^2(6x)+\dfrac{\tan(6x)}{\cos(6x)} \:\:\text{d}x

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Simplify:

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brainly.com/question/27805589

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Step-by-step explanation:

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