To answer this question, we need to find the winning probability in either case.
Probability = no. of outcomes / total no. of possible outcomes
<u>When Hope pulled her defender :</u>
Total no. of games = 9
No. of games won = 3
Winning probability = 3/9 =1/3
<u>When Hope left her defender :</u>
Total no. of games = 10
No. of games won = 6
Winning probability = 6/10 = 3/5
We know that , 1/3 < 3/5.
So, Hope should not pull her defender, as the winning probability is better when Hope left her defender.
Answer : A. Hope should not pull her defender.
Answer:
a) 0.172
b) 0.167
c) 0.1404
Step-by-step explanation:
Margin of error, E = 
here,
p = probability of the event
n = sample size
a) n = 30
p = 10 ÷ 30 = 0.333
Therefore,
E = 
= 2 × 0.0861
= 0.172
b) n = 30
p = 21 ÷ 30 = 0.7
Therefore,
E = 
= 2 × 0.0836
= 0.167
c) n = 30
p = 22 ÷ 50 = 0.44
Therefore,
E = 
= 2 × 0.0702
= 0.1404
Answer:44
Step-by-step explanation:
0.2x+(-0.9)+1.7==9.6
0.2x+0.8=9.6
Subtract 0.8 from both sides
0.2x+0.8-0.8=9.6-0.8
0.2x=8.8
Divide both sides by 0.2
0.2x ➗ 0.2=8.8 ➗ 0.2
x=44
The correct answer would be C
