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gulaghasi [49]
3 years ago
12

Given 32.0 g of water, if we see a temperature change from 25.0°C to 20.0°C, then how much heat energy (q) is transferred from t

he water?
(The specific heat of water is 4.184 J/g°C )
Chemistry
1 answer:
Kamila [148]3 years ago
8 0

Answer:

Q = 669.44 J

Explanation:

Given that,

Mass of water, m = 32 g

The temperature change from 25.0°C to 20.0°C.

We need to find the amount of heat energy transferred. Let it is Q. We know that,

Q=mc\Delta T

Where

c is the specific heat of water

Put all the values,

Q=32\times 4.184 \times (20-25)\\Q=669.44\ J

So, 669.44 J of heat energy is transferred from the water.

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Molecular: Ba(NO₃)₂(aq) + K₂CO₃(aq) → 2K⁺(aq) + 2NO₃¯(aq) + BaCO₃(s) ⬇︎

The complete ionic reaction can be written as follows:

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All the ions in solution have been written out. Now, on to the net ionic equation:

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<h3>what is precipitation?</h3>

Any liquid or frozen water that condenses in the atmosphere and falls to the ground is known as precipitation. Snow, sleet, and rain are just a few of the variations. One of the three main processes that make up the global water cycle is precipitation, along with evaporation and condensation.

Water vapor in the clouds condenses into increasing-sized droplets of water, forming precipitation. Droplets fall to the Earth when they are sufficiently heavy. The water droplets may freeze to produce ice if a cloud is colder, as it would be at higher elevations. Depending on the temperature within the cloud and at the Earth's surface, these ice crystals eventually discharge to the Earth as snow, hail, or rain.

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