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3 years ago

Can photosynthesis occur in the dark if plants are warm?

2 answers:

6 0

No. Photosynthesis happens when there is sunlight. That is how plants make their food. No sunlight, no photosynthesis. If the plant has been taken away from a sunny spot and put in the dark while still warm, it's possible a small amount of photosynthesis could happen.

Anna [14]3 years ago

4 0

No there has to be light

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List two general properties of molecular compounds

Katen [24]

Low melting points and boiling points. ...Low enthalpies of fusion and vaporization These properties are usually one or two orders of magnitude smaller than they are for ionic compounds.Soft or brittle solid forms. ...Poor electrical and thermal conductivity.

5 0

3 years ago

What is the percent by mass of Fluorine in Nitrogen triflouride NF3?

Kipish [7]

Answer:

The answer to your question is 80.3%

Explanation:

Data

Percent by mass of F

molecules NF₃

Process

1.- Calculate the molar mass of nitrogen trifluoride

molar mass = (1 x 14) + (19 x 3)

= 14 + 57

= 71 g

2.- Use proportions and cross multiplications to find the percent by mass of F. The molar mass of NF₃ is equal to 100%.

71 g of NF₃ ------------------ 100%

57 g of F ------------------- x

x = (57 x 100)/71

x = 5700 / 71

x = 80.3%

3.- Conclusion

Fluorine is 80.3% by mass of the molecule NF₃

3 0

3 years ago

4. Which is not an example of unbalanced forces acting on an object

natita [175]

Answer:

did you you know

Explanation: thcco lot iof the

5 0

2 years ago

A 1.800-g sample of solid phenol (C6H5OH(s)) was burned in a bomb calorimeter whose total heat capacity is 11.66 kJ/?C. The temp

vichka [17]

Answer:

The balanced chemical equation:

$C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)$

Heat of combustion per gram of phenol is 32.454 kJ/g

Heat of combustion per gram of phenol is 3,050 kJ/mol

Explanation:

$C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)$

Heat capacity of calorimeter = C = 11.66 kJ/°C

Initial temperature of the calorimeter = $T_1= 21.36^oC$

Final temperature of the calorimeter = $T_2= 26.37^oC$

Heat absorbed by calorimeter = Q

$Q=C\times \Delta T$

Heat released during reaction = Q'

Q' = -Q ( law of conservation of energy)

Energy released on combustion of 1.800 grams of phenol = Q' = -(58.4166 kJ)

Heat of combustion per gram of phenol:

$\frac{Q'}{1.800 g}=\frac{-58.4166 kJ}{1.800 g}=32.454 kJ/g$

Molar mass of phenol = 94 g/mol

Heat of combustion per gram of phenol:

$\frac{Q'}{\frac{1.800 g}{94 g/mol}}=\frac{-58.4166 kJ\times 94 g/mol}{1.800 g}=3,050 kJ/mol$

3 0

3 years ago

Help!!! chemistry electrolysis

Tpy6a [65]

Electrolysis can be used to separate a substance into its original components/elements and it was through this process that a number of elements have been discovered and are still produced in today's industry.

5 0

3 years ago