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3 years ago

How does water move between the hydrosphere and atmosphere?

Chemistry

2 answers:

ratelena [41]3 years ago

7 0

Answer:

here I just googled this for you I hope it helps

Serhud [2]3 years ago

5 0

Answer:

Water moves between the hydrosphere and atmosphere through evaporation condensation and precipitation.

Explanation:

Brainliest plz

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This is a characteristic of the elements in the periodic table that shows a pattern. It may increase or decrease across or down

vaieri [72.5K]

Atomic mass units or AMU

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3 years ago

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What do engineers do while designing solutions to problems? Please 3 sentences or more.

jolli1 [7]

They figure out solutions

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3 years ago

Which of the following sample will have the greatest average speed at 355 K?. A. CH4. B. Ne. C. C2H4. D. Cl2

Amanda [17]

Answer:

The correct option is methane : $CH_4$ .

Explanation:

Average speed of the gas molecules id given by expression:

$v_{avg}=\sqrt{\frac{8kT}{\pi m}}$

k = Boltzmann cosnatnt

T = Temperature of the gas molecules = 355 K

m = molecular mass of the molecule

$v_{avg}\propto \sqrt{\frac{1}{m}}$

Molar mass of methane = 18 g/mol

Molar mass of neon = 20.18 g/mol

Molar mass of ethene = 28 g/mol

Molar mass of chlorine gas = 70 g/mol

Lower the value of molar mass of gas molecule higher will be the average speed.So, from the given options methane gas greatest average seed because it has lowest molecular mass

6 0

3 years ago

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Diatomic iodine [I2] decomposes at high temperature to form I atoms according to the reaction I2(g)⇌2I(g), Kc = 0.011 at 1200∘C

umka2103 [35]

Answer:

The concentration of I at equilibrium = 3.3166×10⁻² M

Explanation:

For the equilibrium reaction,

I₂ (g) ⇄ 2I (g)

The expression for Kc for the reaction is:

$K_c=\frac {\left[I_{Equilibrium} \right]^2}{\left[I_2_{Equilibrium} \right]}$

Given:

$\left[I_2_{Equilibrium} \right]$ = 0.10 M

Kc = 0.011

Applying in the above formula to find the equilibrium concentration of I as:

$0.011=\frac {\left[I_{Equilibrium} \right]^2}{0.10}$

So,

$\left[I_{Equilibrium} \right]^2=0.011\times 0.10$

$\left[I_{Equilibrium} \right]^2=0.0011$

$\left[I_{Equilibrium} \right]=3.3166\times 10^{-2}\ M$

<u>Thus, The concentration of I at equilibrium = 3.3166×10⁻² M</u>

3 0

3 years ago

How many core electrons are in a ground state atom of selenium?

Harman [31]

Electrons in an atom can be classified as core electrons and valence electrons. Valence electrons are those electrons which are present in valence shell and participates in bond formation. While, Core electrons are all remaining electrons which are not present in valence shell, hence not take part in bonding.

Atomic number of Selenium (Se) is 34 hence it has 34 electrons with following electronic configuration;

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁴

From electronic configuration it is found that the valence shell is 4, and the number of electrons present in valence shell are 6. So,

Core Electrons = Total Electrons - Valence Electrons

Core Electrons = 34 - 6

Core Electrons = 28

Result:
There are 28 core electrons in Selenium.

3 0

3 years ago