<span>Consider a angle â BAC and the point D on its defector
Assume that DB is perpendicular to AB and DC is perpendicular to AC.
Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC
Proof
Consider triangles ΔADB and ΔADC
Both are right angle, â ABD= â ACD=90 degree
They have congruent acute angle â BAD and â CAD( since AD is angle bisector)
They share hypotenuse AD
therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
Answer:
5/7 x 4 = 2.8571 in decimal form.
Answer:
1)
angle 2WZX = angle ZYX ( Since all angles and sides of a rhombus are equal)
ZYX = 2 x 29.5
59
2)
4x - 10 =90 (since all angles of a rhombus intersect at 90°)
x=90+10/4
x=100/4
x=25
hope this helps
The page gives you the information that 1 kg is equal to 1000 grams.
This means that you just need to multiply each kg by 1000.
e.g.

Hope this helps!
The answer is most likely 20, if together, they have 26. Basically, 26 - 6 = 20.