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Alinara [238K]
3 years ago
14

51 PTS PLZ DO NOW AND EXPLAIN THE QUESTIONS THE QUESTIONS ARE 9-16

Mathematics
1 answer:
Darina [25.2K]3 years ago
8 0

Answer:

do you have a pic that we can see to help you?

Step-by-step explanation:

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The net of a square pyramid is shown below: Net of a square pyramid showing 4 triangles and the square base. The square base has
Neko [114]

Given:

The dimensions:

Square pyramid

Square base: 2x2

1 out of 4 triangles: 1/2x2x5

4 triangles: 2x2x5

To find:

The SURFACE AREA of the square pyramid

Find answer:

Step 1

Find the area of the square base -

Square base:

SA = L x W

= 2 x 2

= 4

<em>The surface area of the square is 4 square inches</em>

<em></em>

Step 2

Find the area of the 4 Triangles:

We will use a different formula here, to find 1 triangle, we will have to do:

SA = \frac{1}{2} *B*H

To find 2 triangles, we will do:

SA = B*H

But to find 4 triangles in just 1 step, we will do:

SA=2*B*H

Let's do it!

SA = 2*2*5\\=2*10\\=20

<em>The surface area of the 4 triangles are 20 square inches</em>

<em></em>

Step 3

Add answers to get FINAL ANSWER

Easy!

20+4=24

<h2>Hence, the Surface Area of the Square Pyramid is 24 square inches</h2>

<em></em>

<em></em>

4 0
2 years ago
What is the area of the triangle? 24,25,7<br>Pls pls helpp!!!!
Ksju [112]

Answer:

84

Step-by-step explanation:

A= 1/2• bh

A= 1/2•24(7)

3 0
3 years ago
Read 2 more answers
Need help on 2, b, c, and 3 please.
Svetlanka [38]
A/Wall if you have 20 and 30 that box is missing # so you will need to times and you will get something like this 20×30=60 and that's the missing #

B/Its going to be about 768 so you need to times and if you don't get 768


4 0
3 years ago
Polygons ABCD &amp; EFGH are similar. What is the perimeter of EFGH when AD = 12, BC = 8, FE = 15, FG = 10, and GH = 5?
wolverine [178]
Perimeter of EFGH = 50
4 0
3 years ago
PLEASE HELP! BRAINLIEST!
balu736 [363]

Answer:

x=4

Step-by-step explanation:

We can find the length of RT by using the Pythagorean theorem

sin theta = opposite side/ hypotenuse

sin 60 = 2 sqrt(3)/ RT

Multiply each side by RT

RT sin 60 = 2 sqrt(3)

Divide by sin 60

RT = 2 sqrt(3)/ sin 60

RT = 4

Then

tan theta = opposite side/ adjacent side

tan 45 = x/RT

tan 45 = x/4

4 tan 45 = x

4 = x

6 0
3 years ago
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