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myrzilka [38]
3 years ago
8

List at least two questions you can use to help decide whether a website's information is trustworthy

Computers and Technology
1 answer:
alexandr1967 [171]3 years ago
8 0

Answer:

Questions (three) that can be used to decide whether a website's information is trustworthy are;

1) Who is or are the authors of the website

2) What type of information the website conveys

3) Why was the information published on a website

Explanation:

1) Who is or are the authors of the contents of the website including the authors credentials so as to ascertain whether the author is qualified with regards to the topic or topics written about on the website

2) What are the information presented on the website and the context the in which the information are presented

Are the articles in the website backed by a source, with hyperlinks, references or footnotes

3) Why was the on the website information created. Is the information to entertain, persuade, sell or inform

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For what reason can security risks never be fully eliminated?​
raketka [301]

Answer:

A vulnerability level of ZERO can never be obtained since all countermeasures have vulnerabilities themselves. For this reason, vulnerability can never be zero, and thus risk can never be totally eliminated.

Explanation:

also we need to be protected from scams and stuff

7 0
3 years ago
This describes what is charted. It can be placed above or below the chart.
Tems11 [23]

Answer:

a . chart area

This describes what is charted. It can be placed above or below the chart.

Explanation:

3 0
2 years ago
Let's now use our new calculator functions to do some calculations!
Sophie [7]

Answer:

Ans1.

double calc_a;

calc_a=Math.pow(3.0,2.0)+Math.sqrt(9);

Ans2.

double calc_b;

calc_b=((12.0/3.0)-(2.0*4.0));

Ans 3.

double calc_c;

calc_c=(Math.sqrt(16.0)*(7.0+9.0));

Ans 4.

double calc_d;

calc_d=Math.pow(7.0,2.0)/Math.sqrt(49.0);

Explanation:

The expressions are done with Java in answer above.

6 0
3 years ago
Each time an end user clicks a hyperlink, the browser generates a(n) _____ page request that is sent to the designated web serve
igomit [66]

Answer: HTTP GET

Explanation: There are many  HTTP(Hypertext Transfer protocol) requests sent to the server from the client .The page that gets request while the hyperlink page is clicked by the client, opens a HTTP GET page that belongs to the Internet protocol's(IP)suite by server. It is a process for the revival of the data from a particular server. The data does not get effected during the process of the retrieval.

3 0
3 years ago
The Fast as Light Shipping company charges the following rates. Weight of the item being sent Rate per 100 Miles shipped 2kg or
Pie

Answer:

weight = float(input("Enter the weight of the package: "))

distance = float(input("Enter the distance to be sent: "))

weight_charge = 0

if weight <= 2:

   weight_charge = 0.25

elif 2 < weight <= 10:

   weight_charge = 0.3

elif 10 < weight <= 20:

   weight_charge = 0.45

elif 20 < weight <= 50:

   weight_charge = 1.75

if int(distance / 100) == distance / 100:

  d = int(distance / 100)

else:

   d = int(distance / 100) + 1

   

total_charge = d * weight_charge

print("The charge is $", total_charge)

Explanation:

*The code is in Python.

Ask the user to enter the weight and distance

Check the weight to calculate the weight_cost for 100 miles. If it is smaller than or equal to 2, set the weight_charge as 0.25. If it is greater than 2 and smaller than or equal to 10, set the weight_charge as 0.3. If it is greater than 10 and smaller than or equal to 20, set the weight_charge as 0.45. If it is greater than 20 and smaller than or equal to 50, set the weight_charge as 1.75

Since those charges are per 100 miles, you need to consider the distance to find the total_charge. If the int(distance / 100) is equal to (distance / 100), you set the d as int(distance / 100). Otherwise, you set the d as int(distance / 100) + 1. For example, if the distance is 400 miles, you need to multiply the weight_charge by 4, int(400/100) = 4. However, if the distance is 410, you get the int(400/100) = 4, and then add 1 to the d for the extra 10 miles.

Calculate the total_charge, multiply d by weight_charge

Print the total_charge

3 0
2 years ago
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