Ask question

Ask question

All categories

2 years ago

7

Nicole plans to watch 3 movies each month . Write an equation to represent the total number of movies n that she will watch in m

onths .

1 answer:

BartSMP [9]2 years ago

6 0

I’m not sure i understand your question, could you send a picture of the question ??? i want to help you out ☝

You might be interested in

Mrs. Portillo's cat weighs 6 kilograms. Her dog weighs 22 kilograms more than her cat. What is the total weight of her cat and d

topjm [15]

Cat=6
dog=22+6
total kilograms = 6+(22+6)= 34

5 0

3 years ago

Read 2 more answers

Cooper earned $660 as a furniture salesman this month. His earns a

Grace [21]

Ya got to go $660 + 7% hours later on $450 hours later 00.578 to finish

5 0

3 years ago

What is the value of |-7| - |3|<br> A. -10<br> B. -4<br> C. 4<br> D. 10

e-lub [12.9K]

Answer:

10

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Last year Frank had a total income of $58,800. He sold a house and made a profit of $27,940. He also had monthly income of $80 f

xeze [42]

I think the answer would have to be D. $0.90.

59,970-58,800=1,170
1,170/52=22.5/25=0.90

3 0

3 years ago

Read 2 more answers

A car is moving with a velocity (3.0 m/s) x̂ + (1.0 m/s) ŷ and 3.0 seconds later its velocity is (6.0 m/s) x̂ - (3.0 m/s) ŷ. Wha

Mars2501 [29]

Here we know that the initial velocity of the car is given by:

$V_i=(3.0\hat x+1.0\hat y)m/s$

And the final velocity of the car is given by:

$V_f=(6.0\hat x-3.0\hat y)m/s$

It took 3 seconds to attain the final velocity, so we have $t=3 s$

Therefore, the acceleration can be obtained by:

$V_f-V_i=a\times t$

$a=\frac{V_f-V_i}{t}$

Plugging the values of the initial, final velocity and the time, we get:

$a= \frac{(6\hat x-3\hat y)-(3 \hat x+1 \hat y)}{3} =\frac{6\hat x-3 \hat y -3 \hat x-1 \hat y}{3} =\frac{3 \hat x-4 \hat y}{3}$

So the acceleration of the car is given by:

$a=\frac{3 \hat x}{3} -\frac{4 \hat y}{3} =1 \hat x- \frac{4}{3} \hat y$

Now we need to find the direction of the average acceleration of the car:

$\theta=tan^{-1} \frac{y}{x}$

Here, x and y are the coefficients of the 'x' and 'y' components of the vector:

$\theta=tan^{-1}(\frac{-\frac{4}{3} }{1} )=tan^{-1}(\frac{-4}{3}) =-53.13^\circ$

Therefore, the direction of the average acceleration of the car is $-53.13^\circ$ .

8 0

3 years ago