Group 1-lose 1; Group 2-lose 2; Group 13-lose 3; Group 16-gain 2; Group 17-gain 1; Group 18-gain 0
Answer:
Anode: H₂(g) + 2 OH⁻(aq) → 2 H₂O(l) + 2 e⁻
Cathode: 2 Fe⁺³(aq) + 2 e⁻ → 2 Fe⁺²(aq)
E° = 1.60 V
Explanation:
Let's consider the reaction taking place in a galvanic cell.
2 Fe⁺³(aq) + H₂(g) + 2 OH⁻(aq) → 2 Fe⁺²(aq) + 2 H₂O(l)
The corresponding half-reactions are:
Anode (oxidation): H₂(g) + 2 OH⁻(aq) → 2 H₂O(l) + 2 e⁻ E°red = - 0.83 V
Cathode (reduction): 2 Fe⁺³(aq) + 2 e⁻ → 2 Fe⁺²(aq) E°red = 0.77 V
The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.
E° = E°red, cat - E°red, an = 0.77 V - (-0.83 V) = 1.60 V
A model of the atom as they didnt have microscopes back then they used models to describe
Answer:
endothermic reactions
Explanation:
Endothermic reactions are those reactions that absorbs heat from the surroundings as opposed to the exothermic reaction that releases heat energy. This heat absorption that characterizes endothermic reactions causes the surrounding to be cool.
However, in an endothermic reaction, more energy is needed to be absorbed in order to break the bonds of the reactants to form products, hence, making the activation energy of endothermic reactions HIGHER.
Answer:
please give me brainlist and follow
Explanation:
When dilute sulphuric acid is added to barium chloride solution, barium sulphate is formed as a precipitate and hydrogen chloride is formed in aqueous solution.
