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My name is Ann [436]
4 years ago
8

Is the process of a liquid changing into a solid when cooling a chemical reaction?

Chemistry
1 answer:
Alona [7]4 years ago
4 0

Answer: The bulk of liquids separate from the standard substance through crystallization, creating a crystalline block.

Freezing is almost often an exothermic mechanism which ensures that heat is emitted when liquid transforms into concrete.

The energy emitted after freezing, known as the fusion enthalpy, is a latent heat, which is precisely the same as the energy used to melt the same volume of solid.

You might be interested in
In the laboratory a student determines the specific heat of a metal. He heats 19.5 grams of copper to 98.27 °C and then drops it
siniylev [52]

Answer:

The specific heat of copper is 0.37 J/g°C

Explanation:

<u>Step 1: </u>Data given

Mass of copper = 19.5 grams

Initial temperature of copper = 98.27 °C

Mass of water = 76.3 grams

Initial temperature of water = 24.05 °C

Final temperature of water and copper = 25.69 °C

<u>Step 2:</u> Calculate specific heat of copper

Qgained = -Qlost

Q = m*c*ΔT

Qwater = -Qcopper

m(water) * c(water) * ΔT(water) = - m(copper) * c(copper) *ΔT(copper)

⇒ with m(water) = 76.3 grams

⇒ with c(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2-T1 = 25.69 - 24.05 = 1.64

⇒ with m(copper) = 19.5 grams

⇒ with c(copper) = TO BE DETERMINED

⇒ with ΔT(copper) = T2-T1 = 25.69 - 98.27 = -72.58

76.3 * 4.184 * 1.64 = - 19.5 * c(copper) * -72.58

523.552 = 1415.31 * c(copper)

c(copper) = 0.37 J/g°C

The specific heat of copper is 0.37 J/g°C

3 0
4 years ago
Balance the following equation and list the coefficients in order from left to right.
Lapatulllka [165]

Vascular tissue

From Wikipedia, the free encyclopedia

Jump to navigationJump to search

Cross section of celery stalk, showing vascular bundles, which include both phloem and xylem.

Detail of the vasculature of a bramble leaf.

Translocation in vascular plants

This article is about vascular tissue in plants. For transportation in animals, see Circulatory system.

Vascular tissue is a complex conducting tissue, formed of more than one cell type, found in vascular plants. The primary components of vascular tissue are the xylem and phloem. These two tissues transport fluid and nutrients internally. There are also two meristems associated with vascular tissue: the vascular cambium and the cork cambium. All the vascular tissues within a particular plant together constitute the vascular tissue system of that plant.

The cells in vascular tissue are typically long and slender. Since the xylem and phloem function in the conduction of water, minerals, and nutrients throughout the plant, it is not surprising that their form should be similar to pipes. The individual cells of phloem are connected end-to-end, just as the sections of a pipe might be. As the plant grows, new vascular tissue differentiates in the growing tips of the plant. The new tissue is aligned with existing vascular tissue, maintaining its connection throughout the plant. The vascular tissue in plants is arranged in long, discrete strands called vascular bundles. These bundles include both xylem and phloem, as well as supporting and protective cells. In stems and roots, the xylem typically lies closer to the interior of the stem with phloem towards the exterior of the stem. In the stems of some Asterales dicots, there may be phloem located inwardly from the xylem as well.

Between the xylem and phloem is a meristem called the vascular cambium. This tissue divides off cells that will become additional xylem and phloem. This growth increases the girth of the plant, rather than it

6 0
3 years ago
How many kilojoules of heat are absorbed when 2.00 L of water is heated from 19*C to 80*C? (Show all work including the equation
Snowcat [4.5K]

Answer:

The answer to your question is 510.7 kJ

Explanation:

Data

Q = ?

Volume = 2 L

Temperature 1 = T1 = 19°C

Temperature 2 = T2 = 80°C

Specific heat = 4.186 J/kg°C

Density of water = 1 g/ml

Equation

              Q = mC(T2 - T1)

Process

1.- Calculate the mass of water

mass = density x volume

mass = 1 x 2000

mass = 2000 g

2.- Substitute values in the Heat formula

              Q = (2000)(4.186)(80 - 19)

-Simplification

               Q = (2000)(4.186)(61)

-Result

              Q = 510692 J  or 510.7 kJ

7 0
4 years ago
5. How would you calculate the pH (NOT POH) of a base when given<br><br> the concentration of [OHJ?
PIT_PIT [208]

Answer:

pOH = -log₁₀ [OH-]

pH = 14 - pOH

Explanation:

First of all, calculate the value of pOH from  the hydroxide concentration do this using the equation below;

pOH = -log₁₀ [OH-]

After obtaining the pOH, calculate pH using the equation below:

pH + pOH = 14

pH = 14 - pOH

3 0
3 years ago
Classify the following as acid-Base reactions or oxidation-reduction reactions:
postnew [5]

Explanation:

(a) Na_2S+HCl\rightarrow H_2S+2NaCl

This is acid base reaction because there is no change of oxidation state on either side of the reaction.

(b) 2Na+2HCl\rightarrow H_2+2NaCl

This is a oxidation reduction reaction because sodium in elemental state ( 0 oxidation state) oxidizes to Na⁺ in NaCl. Also H⁺ in HCl reduces to H° in H₂.

(c) Mg+Cl_2\rightarrow MgCl_2

This is a oxidation reduction reaction because magnesium in elemental state ( 0 oxidation state) oxidizes to Mg²⁺ in MgCl₂. Also Cl° in Cl₂ reduces to Cl⁻ in  MgCl₂.

(d) MgO+2HCl\rightarrow H_2O+MgCl_2

This is acid base reaction because there is no change of oxidation state on either side of the reaction.

(e) K_3P+2O_2\rightarrow K_3PO_4

This is a oxidation reduction reaction because phosphorous in P³⁻ in K₃P oxidizes to P⁵⁺ in K₃PO₄ and oxygen reduces.

(f) 3KOH+H_3PO_4\rightarrow K_3PO_4 + 3H_2O

This is acid base reaction because there is no change of oxidation state on either side of the reaction.

4 0
4 years ago
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