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frez [133]
3 years ago
13

3 mA are flowing through an 18 V circuit, how much resistance (in kΩ) is in that circuit?

Engineering
1 answer:
Sergio [31]3 years ago
5 0

Answer:

6kΩ

Explanation:

If we assume that the entire circuit's current is 3 mA, then we can compute the resistance within the circuit with the application of Ohm's law:

V = IR

V/I = R

R = V / I

R = 18V / 3 mA

R = 6kΩ

Hence, the resistance of the circuit is 6kΩ.

Cheers.

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