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3 years ago

9 b. A sign (including the post and base) weighs 40 pounds and is

Engineering

1 answer:

tigry1 [53]3 years ago

8 0

Answer:

The weight should be added to the base of the sign to keep it from tipping is 65.6 lb

Explanation:

Given data:

A sigh weighs 40 pounds

Suported by an 18 in x 18 in square

Force of the wind 13.2 lb

Questions: Will the sign tip over, if yes, how much evelnly distributed weight should be added to the base of the sign to keep it from tipping, W = ?

The sign and the post have a length of 6 ft. You need to calculate the distance from the edge to the middle point:

18/2 = 9 in = 0.75 ft

Force acting in the base (40 lb):

$F=\frac{40*0.75}{6} =5lb$

The weight should be added to the base:

$(40+W)*\frac{0.75}{6} =13.2\\W=65.6lb$

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Explanation:

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where,

$P_1$ = initial pressure of gas = 150 kPa

$P_2$ = final pressure of gas = ?

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4 years ago

) A shaft encoder is to be used with a 50 mm radius tracking wheel to monitor linear displacement. If the encoder produces 256 p

andrey2020 [161]

Answer:

number of pulses produced = 162 pulses

Explanation:

give data

radius = 50 mm

encoder produces = 256 pulses per revolution

linear displacement = 200 mm

solution

first we consider here roll shaft encoder on the flat surface without any slipping

we get here now circumference that is

circumference = 2 π r .........1

circumference = 2 × π × 50

circumference = 314.16 mm

so now we get number of pulses produced

number of pulses produced = $\frac{linear\ displacement}{circumference}$ × No of pulses per revolution .................2

number of pulses produced = $\frac{200}{314.16}$ × 256

number of pulses produced = 162 pulses

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3 years ago

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Answer:

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