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DedPeter [7]
4 years ago
8

9 b. A sign (including the post and base) weighs 40 pounds and is

Engineering
1 answer:
tigry1 [53]4 years ago
8 0

Answer:

The weight should be added to the base of the sign to keep it from tipping is 65.6 lb

Explanation:

Given data:

A sigh weighs 40 pounds

Suported by an 18 in x 18 in square

Force of the wind 13.2 lb

Questions: Will the sign tip over, if yes, how much evelnly distributed weight should be added to the base of the sign to keep it from tipping, W = ?

The sign and the post have a length of 6 ft. You need to calculate the distance from the edge to the middle point:

18/2 = 9 in = 0.75 ft

Force acting in the base (40 lb):

F=\frac{40*0.75}{6} =5lb

The weight should be added to the base:

(40+W)*\frac{0.75}{6} =13.2\\W=65.6lb

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Answer:

Employers must comply with OSHA's regulations to safeguard workers from caught-in or -between dangers, which include, but are not limited to, the following:

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Explanation:

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3 years ago
9 Consider fully developed conditions in a circular tube with constant surface temperature Ts Tm. Determine whether a small- or
mojhsa [17]

Answer:

Hello your question is incomplete attached below is the complete question

answer:

Considering Laminar flow

Q ( heat )  will be independent of diameter

Considering Turbulent flow

The heat transfer will increase with decreasing "dia" for the turbulent

heat transfer = f(d^-0.8 )

Explanation:

attached below is the detailed solution

Considering Laminar flow

Q ( heat )  will be independent of diameter

Considering Turbulent flow

The heat transfer will increase with decreasing "dia" for the turbulent

heat transfer = f(d^-0.8 )

6 0
3 years ago
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gogolik [260]
Short-term goals are planned for the near future while long-term goals will take longer to complete. An example of a short-term goal is trying to get into a certain college. A long-term goal is wanting to have a big family.
3 0
3 years ago
A rocket is to be designed to produce 5 MN of thrust at sea level. The pressure in the combustion chamber is 7 MPa and the tempe
tiny-mole [99]

Answer:

a) specific impulse = 203 s

(b) mass flow rate = 2511 kg/s

(c) throat diameter = 0.774 m

(d) exit diameter = 1.95 m

(e) thrust =  5.3*10^6 N/m^2

(f) thrust at sea level = 15.6*10^6 N

(g) thrust with hydrogen = 5*10^6 N

(h) thrust with stagnation =  5*10^6 N

Explanation:

See the attached file for explanation.

7 0
4 years ago
Consider the control volume form of the basic laws. For the conservation of mass form for a control volume with mass flow into a
aleksandrvk [35]

Answer:

C) Dependent on the mass flows in and out.

Explanation:

Lets take control volume(CV)

Take

          m_i =inlet mass flow rate

          m_e =exit mass flow rate

If we take unsteady flow process then inlet mass can not be equal to exit mass.Some mass can store if inlet mass flow rate is high and exit mass flow rate  is low.

So mass of control volume

    m_{cv}=m_i-m_e.

so above we can say that mass of control volume dependent on inlet and exit mass.

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