We will see that f'(x) > 0, which means that f(x) is an increasing function.
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How to prove that the function is increasing?</h3>
For any function f(x), if f'(x) > 0, then f(x) is increasing for any value of x.
Here we have the cubic function:
f(x) = x³ + 4x
If we differentiate this, we get:
f'(x) = df(x)/dx = 3x² + 4.
And notice that x² is always positive, then f'(x) > 0, which means that f(x) is an increasing function.
If you want to learn more about cubic functions:
brainly.com/question/20896994
#SPJ1
If the answer is talking about rounding to 1 thousand then that means it is 64,000,000
Answer:
i believe the correct answer is C.
Step-by-step explanation:
Answer:
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The discount is $1,880 and the selling price is $21,620, make sure to put the dollar sign to make sure you know what the number means
