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Tanya [424]
3 years ago
8

Water flows over a fall that is 125.0 m high. If the potential energy of the water is all converted to thermal energy, calculate

the temperature difference between the water at the top and the bottom of the fall.
Physics
1 answer:
Pavel [41]3 years ago
8 0

Answer:

ΔT = 0.29°C

Explanation:

Using the law of conservation of energy:

Potential\ Energy = Thermal\ Energy\\mgh = mC\Delta T\\gh = C\ \Delta T\\\\\Delta T = \frac{gh}{C}

where,

ΔT = Temperature difference between the water at the top and the bottom of the fall = ?

g = acceleration due to gravity = 9.81 m/s²

h = height of fall = 125 m

C = specific heat capacity of water = 4200 J/kg

Therefore,

\Delta T = \frac{(9.81\ m/s^2)(125\ m)}{4200\ J/kg^oC}\\\\

<u>ΔT = 0.29°C</u>

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Ok, Rameses:

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It would be so easy to check this work of mine ...
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