Answer:
4.78 kg/m^2.
Explanation:
τ = Iα
Where,
τ = torque, around a defined axis (N∙m)
I = moment of inertia (kg∙m2)
α = angular acceleration
= 1.2 rad/s^2
τ = F * r
= 16.88 * 0.34
= 5.74 N.m
Therefore, I = 5.74/1.2
= 4.78 kg/m2
V = IR
Where:
V = Voltage
I = Current
R = Resistance
F(in) x d(in)= F(out)x d(out)
A machine has a mechanical advantage of 5.
F(out )= 5xF(in)300 newtons
F(in) = 300 N
F(out)= 5xF(in) = 5x300 N
= 1500 N
Work in = Work out = 3000 N x m3000
N x m = F_in x d_ind_in = 3000 Nxm / F_in = 3000 N x m / 300 N = 10 m3000 Nxm = F_out x d_out d_out = 3000 Nx m / F_out = 3000 N x m / 1500 N = 2 m
Explanation:
PE= mgh
6 J= (3m) (9.81 m/s2) (mass)
mass=( 6)/(3×9.81)
mass= 0.20 Kg
