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iogann1982 [59]
3 years ago
15

-Which of the following wires will have the least resistance?

Physics
2 answers:
scoray [572]3 years ago
7 0
The wires that will have the least resistance is :
C. A short thick wire
in order to get the least resistence, you need the wire to be the lowest in length and the highest in Area

hope this helps
Pani-rosa [81]3 years ago
5 0

Answer:

Option (C)

Explanation:

The obstruction offered by the conductor in the path of flow of electrons is called the resistance of the conductor.

The reistance of the conductor is directly proportional to the length of the conductor and inversely proportional to the area of crossection of the conductor.

To minimize the resistance we need a wire of short length and more crossection area.

So, wire should be short and thick.

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What is physics meaning
Maurinko [17]

Answer:

the branch of science concerned with the nature and properties of matter and energy. The subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms.

physics, science that deals with the structure of matter and the interactions between the fundamental constituents of the observable universe. In the broadest sense, physics (from the Greek physikos) is concerned with all aspects of nature on both the macroscopic and submicroscopic levels.

8 0
2 years ago
Read 2 more answers
The best leaper in the animal kingdom is the puma, which can jump to a height of 3.7m when leaving the ground at an angle of 45
zheka24 [161]

Answer:

v = 12 m/s

Long, boring, and convoluted explanation:

First, let's lay out our information.

- <em>max height = 3.7 m</em>

- <em>0 = 45°</em>

<em>- gravitational acceleration constant = 9.8 </em>\frac{m}{s^2}<em />

<em />

Since the puma leaves the ground at a <em> 45 °</em> angle, its motion will follow a curved path as seen in many projectile motion problems, where the object is being influenced solely by the force of gravity. And because the puma leaves the ground at an angle, its initial velocity is broken down into its horizontal and vertical components. We were also told, though indirectly, that the max height is  <em>3.7m</em>  because the puma can reach up to that height. Gravity is always given to be <em>9.8 </em>\frac{m}{s^2}<em />

<em />

Because we are dealing with maximum height and gravity, we have to use the vertical component of the velocity,  <em>vsin ( θ )</em> , and not the horizontal component, <em>vcos ( θ )</em> .

Given its max height, the acceleration due to gravity, and the angle, we can now solve for the speed at which the puma leaves the ground using the following equation: <em>vsin ( θ )  = </em> \sqrt{2hg}

Where <em> vsin ( θ )</em>  is the vertical component of the initial velocity and <em>h</em>  and <em>g</em> are max height and gravitational acceleration constant respectively.

Plugin, rearrange and solve

v sin ( θ )  =  \sqrt{2hg}

v sin ( 45 ∘ )  =   √ 2  ×  3.7  ×  9.8

v ( 0.71 )  =  \sqrt{72.52}

v ( 0.71 )  =  8.52

v  =  8.52 /0.71

v =  12 m s

<em />

<em />

4 0
3 years ago
A 0.42 kg soccer ball is moving down field with a velocity of 12 m/s. A player kicks the ball so that it has a final velocity of
KATRIN_1 [288]

Answer:

the change in momentum is 2.52 N·s

the constant force on the ball while in contact with the players foot is 126 N

Explanation:

p=momentum

m=mass

v=change in velocity

p=(0.42)(6)

p=2.52

8 0
3 years ago
If the period of a wave increases, its frequency must
Bumek [7]
Decrease.
Hopefully this helped:)
8 0
3 years ago
Read 2 more answers
A 0.40 kg block can slide up and down a rough a 10-m-high, 30-m-long slope. At the bottom, a stiff spring with spring constant 8
Paul [167]

Answer:

v=11.135m/s

Explanation:

From the question we are told that

Mass m=0.40kg

Frictional friction f=1.2

Spring constant k=800N/m

Compressed x=0.50

Generally the energy balance equation is mathematically given as

1/2kx^2=f*30+m*g*sin \theta*30+1/2m*v^2

if (sin=10/30-1/3)

1/2(800)(0.5)^2=(1.2)*30+(0.4)*9.8*1/3*30+1/2(0.4)*v^2

100=36+39.2+0.20v^2

v^2=\frac{24.8}{0.20}

v=\sqrt{124}

v=11.135m/s

8 0
3 years ago
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