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iogann1982 [59]
3 years ago
15

-Which of the following wires will have the least resistance?

Physics
2 answers:
scoray [572]3 years ago
7 0
The wires that will have the least resistance is :
C. A short thick wire
in order to get the least resistence, you need the wire to be the lowest in length and the highest in Area

hope this helps
Pani-rosa [81]3 years ago
5 0

Answer:

Option (C)

Explanation:

The obstruction offered by the conductor in the path of flow of electrons is called the resistance of the conductor.

The reistance of the conductor is directly proportional to the length of the conductor and inversely proportional to the area of crossection of the conductor.

To minimize the resistance we need a wire of short length and more crossection area.

So, wire should be short and thick.

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The hydraulic oil in a car lift has a density of 8.53 x 102 kg/m3. The weight of the input piston is negligible. The radii of th
navik [9.2K]

Answer:

(a) the input force is 36.56 N

(b) the input force is 37.49 N

Explanation:

Given;

density of hydraulic oil, ρ =  8.53 x 10² kg/m³

radius of plunger, r₁ = 0.135 m

radius of piston, r₂ = 5.43 x 10⁻³ m

Part (a) The input force needed to support 22600-N weight, when the bottom surfaces of the piston and plunger are at the same level;

P =\frac{F}{A}

Where;

P is pressure

F is force

A is circular area = πr²

\frac{F_1}{A_1} =\frac{F_2}{A_2} \\\\F_2 = \frac{F_1*A_2}{A_1} =\frac{F_1* \pi r_2^2}{\pi r_1^2} = \frac{F_1*  r_2^2}{ r_1^2} \\\\F_2 = \frac{22600*(5.43*10^{-3})^2 }{(0.135)^2}\\\\F_2 = 36.56 \ N

Part (b) The input force needed to support 22600-N weight, when the  bottom surface of the output plunger is 1.20 m above that of the input plunger

P_2 = P_1 + \rho gh

But, F = PA  and  A = πr²

F_2 = F_1(\frac{A_2}{A_1} ) + \rho gh*A_2\\\\F_2 = F_1(\frac{r_2^2}{r_1^2} )+\rho gh(\pi r_2^2)\\\\F_2 = 22600(\frac{5.43*10^{-3}}{0.135})^2 \ + 853*9.8*1.2*\pi (5.43*10^{-3})^2\\\\F_2=36.56 + 0.93\\\\F_2 = 37.49 \ N

4 0
3 years ago
A ball is kicked horizontally from a 60 meter tall cliff at 10 m/s. How far from
o-na [289]

Hi there!

We can begin by deriving the equation for how long the ball takes to reach the bottom of the cliff.

\large\boxed{\Delta d = v_it+ \frac{1}{2}at^2}}

There is NO initial vertical velocity, so:

\large\boxed{\Delta d= \frac{1}{2}at^2}}

Rearrange to solve for time:

2\Delta d = at^2\\\\t = \sqrt{\frac{2\Delta d}{g}}

Plug in the given height and acceleration due to gravity (g ≈ 9.8 m/s²)

t = \sqrt{\frac{2(60)}{(9.8)}} = 3.5 s

Now, use the following for finding the HORIZONTAL distance using its horizontal velocity:

\large\boxed{d_x = vt}\\\\d_x = 10(3.5) = \karge\boxed{35 m}

6 0
3 years ago
The activity of mining has direct negative effects on
Rom4ik [11]

Answer:

A

Explanation:

When coal is burned it releases many harmful chemicals into the air, such as methane (greenhouse gas) and contributes to global warming

4 0
3 years ago
When the rate of motion is the same direction the speed will decrease.<br><br> True<br> False
slega [8]
A)true is the answer
6 0
3 years ago
Show that liquid pressure is directly<br>proportional to height of liquid in a vessel.​
Norma-Jean [14]

Answer:

P=F/A where F is the weight of the water and A is the area on which it is resting. The weight of the water is mg. The mass of the water is dv where d is the density and v is the volume. Finally, the volume of the water in a vessel is equal to the area of the base of the vessel times the height of the vessel. (v=Ah)

Plugging everything in we get:

P = dAhg/A

So

P=dhg

So we have shown that liquid pressure is directly  proportional to height of liquid in a vessel.​

7 0
3 years ago
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