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iogann1982 [59]

2 years ago

15

-Which of the following wires will have the least resistance?

2 answers:

scoray [572]2 years ago

7 0

The wires that will have the least resistance is :
C. A short thick wire
in order to get the least resistence, you need the wire to be the lowest in length and the highest in Area

hope this helps

Pani-rosa [81]2 years ago

5 0

Answer:

Option (C)

Explanation:

The obstruction offered by the conductor in the path of flow of electrons is called the resistance of the conductor.

The reistance of the conductor is directly proportional to the length of the conductor and inversely proportional to the area of crossection of the conductor.

To minimize the resistance we need a wire of short length and more crossection area.

So, wire should be short and thick.

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A rock climber hangs freely from a nylon rope that is 15 m long and has a diameter of 8.3 mm. If the rope stretches 5.1 cm, what

irinina [24]

Answer:

Mass of the climber = 69.38 kg

Explanation:

Change in length

$\Delta L=\frac{PL}{AE}$

Load, P = m x 9.81 = 9.81m

Young's modulus, Y = 0.37 x 10¹⁰ N/m²

Area

$A=\frac{\pi (8.3\times 10^{-3})^2}{4}=5.41\times 10^{-5}m^2$

Length, L = 15 m

ΔL = 5.1 cm = 0.051 m

Substituting

$0.051=\frac{9.81m\times 15}{5.41\times 10^{-5}\times 0.37\times 10^{10}}\\\\m=69.38kg$

Mass of the climber = 69.38 kg

6 0

2 years ago

What role does a resistor play in an electrical circuit

kirza4 [7]

Answer: It opposes the flow of electrons.

Explanation: just did the quiz on

4 0

2 years ago

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ddd [48]

Answer:

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8 0

2 years ago

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Lena [83]

Answer:

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Explanation:

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8 0

1 year ago

A zebra starts from rest and accelerates at 1.9 m/s, how far has the zebra gone after 5 seconds

Aliun [14]

Answer:

23.8 m

Explanation:

The distance travelled by the zebra can be calculated by using the equation:

$d=ut+\frac{1}{2}at^2$

where

u is the initial velocity

t is the time

a is the acceleration

For this zebra,

u = 0 since it starts from rest

$a=1.9 m/s^2$ is the acceleration

Substituting t = 5 s, we find the distance travelled by the zebra:

$d=0+\frac{1}{2}(1.9)(5)^2=23.8 m$

5 0

2 years ago