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Snezhnost [94]
3 years ago
11

What is the formula for diblackur triorangide?

Chemistry
1 answer:
SashulF [63]3 years ago
7 0

Answer:

stop trolling

Explanation:

this does not exist

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Two examples of organic chemical
spayn [35]

Answer:

there are literally millions - alkanes, alkenes, alkynes, alcohols, esters, carboxylic acids... to name but a few.

Explanation:

6 0
3 years ago
The protein lysozyme unfolds at a transition temperature of 75.5°C, and the standard enthalpy of transition is 509 kJ mol-1. Cal
spin [16.1K]

Answer:

0.4774 KJ/K.mol

Explanation:

We are told that the transition at 25.0°C occurs in three steps. Steps i, ii and iii.

Thus;

the entropy of unfolding of lysozyme = ΔS_i + ΔS_ii + ΔS_iii

Now,

C_p,m(unfolded protein) = C_p,m(folded protein) + 6.28 kJ/K.mol

Now, for the first process, ΔS_i is given as;

ΔS_i = C_p,m × In(T2/T1)

We are given;

T1 = 25°C = 25 + 273.15K = 298.15 K

T2 = 75.5°C = 75.5 + 273.15 K=348.65 K

Thus;

ΔS_i = C_p,m × In(348.65/298.15)

Now, for the third process, ΔS_iii is given as;

ΔS_iii = (C_p,m + 6.28 kJ/K.mol) × In(T1/T2)

Thus;

ΔS_iii = (C_p,m + 6.28 kJ/K.mol) × In(298.15/348.65)

Now, we don't know C_pm. So, we have to find a way to eliminate it. We will do it by rewriting In(298.15/348.65) in such a way that when ΔS_iii is added to ΔS_i, C_p,m will cancel out. Thus;

In(298.15/348.65) can also be written as;

In(348.65/298.15)^(-1) or

- In(348.65/298.15)

Thus;

ΔS_iii = - [(C_p,m + 6.28 kJ/K.mol) × In(298.15/348.65)]

Now, let's add ΔS_iii to ΔS_i to get;

ΔS_i + ΔS_iii = [C_p,m × In(348.65/298.15)] + [(-C_p,m - 6.28 kJ/K.mol) × In(348.65/298.15)]

ΔS_i + ΔS_iii = [C_p,m × In(348.65/298.15)] - [C_p,m × In(348.65/298.15)] - [6.28In(348.65/298.15)]

First 2 terms will cancel out to give;

ΔS_i + ΔS_iii = -6.28In(348.65/298.15)

ΔS_i + ΔS_iii = -0.9826 KJ/K.mol

Now,for process ii;

ΔS_ii = standard enthalpy of transition/Transition Temperature

Thus;

ΔS_ii = (509 KJ/K.mol)/348.65

ΔS_ii = 1.46 KJ/K.mol

Thus;

the entropy of unfolding of lysozyme = ΔS_i + ΔS_ii + ΔS_iii = -0.9826 + 1.46 = 0.4774 KJ/K.mol

5 0
3 years ago
Consider the following reversible reaction. 2H2O(g)<—>2H2(g)+O2(g) What is the equilibrium constant expression for the giv
masha68 [24]

The reaction: 2H2(g) + O2(g) → 2H2O(g), can be interpreted as: a. 2 moles of hydrogen gas reacts with 1 mole of oxygen gas to produce 2 moles of water.

7 0
3 years ago
Read 2 more answers
Laser fusion Group of answer choices uses chemical reactions to produce energy uses nuclear reactions to produce energy implodes
KonstantinChe [14]

Answer:

Uses nuclear reactions to produce energy

Implodes a fuel pellet

Explanation:

Laser fusion is a method of initiating nuclear fusion reactions through heating, and compressing fuel pellets containing deuterium and tritium using high energy density laser beams. Lase fusion is also known as inertial confinement fusion and the energy produced by the process is known as Laser Inertial Fusion Energy, LIFE.

During the process of laser fusion, small pellets of deuterium-tritium (DT) isotopes mixture are fed into a blast chamber where they are compressed to high densities using a number of amplified laser beams in the chamber.

The high energy density of the beams as well as the heat produced due to compression, induces the thermonuclear explosion ignition resulting in the production of high energetic products such as charged particles, x-rays and neutrons. The energy produced is absorbed and stored as heat in a blanket that is then used in a steam thermal cycle to generate electrical power.

There are two methods of compression of the DT pellet: direct and indirect-drive laser fusions.

However, there are a number of limitations to energy production by this process. One limitation is that the process is extremely inefficient in energy energy production. Also, the heat produced by the flashtubes results innthe deformation of the laser glass.

3 0
3 years ago
Explain specifically how an electron gives off light in an atom.
exis [7]

Answer:

Then, at some point, these higher energy electrons give up their "extra" energy in the form of a photon of light, and fall back down to their original energy level.

Explanation:

When properly stimulated, electrons in these materials move from a lower level of energy up to a higher level of energy and occupy a different orbital.

3 0
2 years ago
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