Answer:
This question is incomplete, here's the complete question:
<em><u>"Suppose 0.0842g of potassium sulfate is dissolved in 50.mL of a 52.0mM aqueous solution of sodium chromate. Calculate the final molarity of potassium cation in the solution. You can assume the volume of the solution doesn't change when the potassium sulfate is dissolved in it. Round your answer to 2 significant digits."</u></em>
Explanation:
Reaction :-
K2SO4 + Na2CrO4 ------> K2CrO4 + Na2SO4
Mass of K2SO4 = 0.0842 g, Molar mass of K2SO4 = 174.26 g/mol
Number of moles of K2SO4 = 0.0842 g / 174.26 g/mol = 0.000483 mol
Concentration of Na2CrO4 = 52.0 mM = 52.0 * 10^-3 M = 0.052 mol/L
Volume of Na2CrO4 solution = 50.0 ml = 50 L / 1000 = 0.05 L
Number of moles of Na2CrO4 = 0.05 L * 0.052 mol/L = 0.0026 mol
Since number of moles of K2SO4 is smaller than number of moles Na2CrO4, so 0.000483 mol of K2SO4 will react with 0.000483 mol of Na2CrO4 will produce 0.000483 mol of K2CrO4.
0.000483 mol of K2CrO4 will dissociate into 2* 0.000483 mol of K^+
Final concentration of potassium cation
= (2*0.000483 mol) / 0.05 L = 0.02 mol/L = 0.02 M
The substance has a higher density than water
The formula for hydrogen-hydrogen is H-H
Answer:
Points of acceleration:
1. When female bear goes quickly
2. After becoming tired, when she becomes slow
3. When she changes direction from east to north
4.When she slows down when she reaches the river bed
5. When she turns around
6.When she increases speed to travel southwest to return home
7. When she comes to a stop at home
Explanation:
1. When she is going quickly she is increasing her velocity thus positively accelerating
2. When she becomes slow, she is having negative acceleration.
3. When there is a change in direction of velocity there is an acceleration.
4. Again negative acceleration when she comes to a stop at the river bed
5. Turning around to the southwest direction requires acceleration
6. To increase the velocity to reach home, positive acceleration
7. To decrease the velocity to stop upon reaching home, negative acceleration
CuSO₄·5H₂O the pentahydrate is the most common form
[Cu(H₂O)₄]SO₄·H₂O → [Cu(H₂O)₄]²⁺ + SO₄²⁻ + H₂O
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