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4 years ago

PLEASE HELP WHICH STATEMENTS ARE CORRECT DO NOT GUESS

Physics

2 answers:

Anni [7]4 years ago

8 0

THe first one and the third one!!

Lelechka [254]4 years ago

3 0

Answer:

Explanation:

Use the diagram and drop-down menus to answer each question.

Which circuit is a parallel circuit?____ [B]

Which circuit is a series circuit?____ [A]

In which circuit do the light bulbs all shine at their maximum brightness? _[B]

Those are the answer for edgenuit.....

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Question: How is a triple beam balance used to find mass?1. Observe: The riders have masses of 10 grams (top), 100 grams (middle

ozzi

Answer:

1) For the weight to be correct, the pointer must be below the reference (zero) or in it

2) mass greater than 300 g leave the pointer below the reference,

3) put weight on the other arms the pointer gets closer to the reference

Explanation:

1) A three-arm scale is used to determine the weight of a body by successive approximations, starting with the arm with the greatest mass (middle), when the pointer is close to zero without going over, weights are placed on the second arm (above ) weight is placed to bring the pointer closer to the reference without going over and when it is used the arm with the lowest mass is used (below) with this one, masses are placed until reaching the reference,

Taking all the jinetillos placed the total weight, the product of the position of the jinetillo by the precision of the arm and then the three values are added.

In the example given, the jinetillo is placed in position 3 of the 100 arm, so the weight is 300 gr.

For the weight to be correct, the pointer must be below the reference (zero) or in it

2) objects with a mass greater than 300 g leave the pointer below the reference, it must be completed with the other two arms to reach the correct weight

3) when you put weight on the other arms the pointer gets closer to the reference

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4 years ago

Convection currents form when warm air rises and cold air sinks. What causes the warm air to rise and the cold air to sink? A. a

Kitty [74]

<span>B. a difference in density</span>

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4 years ago

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A circular wire loop of radius LaTeX: RR lies in the xy-plane with the z-axis running through its center. There is initially no

frosja888 [35]

Answer:

Explanation:

Given a circular loop of radius R

r = R

Note: the radius lies in the xy plane

Area is given as

A = πr² = πR²

At t = 0, no magnetic field B=0

The magnetic field is given as a function of time

B = C•exp(t) •i + D•t² •k

Where C and D are constant

We want to find the magnitude of EMF in the circular loop.

EMF is given as

ε = - N•dΦ/dt

Where,

N is number of turn and in this case we will assume N = 1.

Φ is magnetic flux and it is given as

Φ = BA

ε = - N•d(BA)/dt

Where A is a constant, then we have

ε = - N•A•dB/dt

B = C•exp(t) •i + D•t² •k

dB/dt = C•exp(t) •i + 2D•t •k

Then,

ε = - N•A•dB/dt

ε = - 1•πR²•(C•exp(t) •i + 2D•t •k)

ε = -πR²•(C•exp(t) •i + 2D•t •k)

So, let find the magnitude of EMF

Generally finding magnitude of two vectors R = a•i + b•j

Then, |R| = √a² + b²

So, applying this we have,

ε = πR² (√(C²•exp(2t) + 4D²t²))

From the given magnetic field, we are given that,

B = 0 at t = 0

B = C•exp(t) •i + D•t² •k

B = 0 = C•exp(0) •i + D•0² •k

0 = C

Then, C = 0.

So, substituting this into the EMF.

ε = πR² (√(0²•exp(2t) + 4D²t²))

ε = πR² (√4D²t²)

ε = πR² × 2Dt

ε = 2πDR²t

So, the EMF is also a function of time

ε = 2πDR²t

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4 years ago

You build a solenoid containing 500 windings over a 0.20-m length, with a loop radius of 0.025 m for each winding. the current i

marta [7]

The inductance of a solenoid is given by:
$L= \frac{\mu_0 N^2 A}{l}$
where
$\mu_0$ is the vacuum permeability
N is the number of turns of the solenoid
A is the area of one loop of the solenoid
l is its length

For the solenoid in our problem, N=500, and the radius of one loop is r=0.025 m, so the area of one loop is
$A=\pi r^2 = \pi (0.025 m)^2 = 1.96 \cdot 10^{-3} m^2$
and its length is l=0.20 m

So the inductance of the solenoid is
$L= \frac{(4 \pi \cdot 10^{-7} NA^{-2})(500)^2(1.96 \cdot 10^{-3} m^2)}{ 0.20 m}=3.08 \cdot 10^{-3} H$

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4 years ago

After a nucleus undergoes radioactive decay, its new mass number is:

Ivanshal [37]

Radioactive "decay" means particles and stuff shoot OUT of a nucleus.
After that happens, there's less stuff in the nucleus than there was before.
So the new mass number is always less than the original mass number.

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