Explanation:
∆x=300 m×2
∆t=1.5 s
v=∆x/∆t → v=2×300/1.5 = 400 m/s
Answer:
mass of box 1 = 2.20 kg
mass of box 2 = 5.93 kg
Explanation:
Let the mass of box 1 and box 2 is respectively
and 
so we will have
Force applied on box 1 then acceleration



Now we know that contact force between them in above case is given as



now we have

Answer:
6.75m/s
Explanation:
using the second equation of motion, the time is calculated.
and with the formula a= (v - u)/t
where a is acceleration but in this case it's deceleration (and should be negated as you solve it ) .
v is final velocity
u is initial velocity
t is time taken