H. Briefly describe the process taking place in the image below and comment on the
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For a cylinder that has both ends open resonant frequency is given by the following formula:
Where n is the resonance node, v is the speed of sound in air and L is the length of a cylinder.
The fundamental frequency is simply the lowest resonant frequency.
We find it by plugging in n=1:
To find what harmonic has to be excited so that it resonates at f>20Hz we simply plug in f=20 Hz and find our n:
We can see that any resonant frequency is simply a multiple of a base frequency.
Let us find which harmonic resonates with the frequency 20 Hz:
Since n has to be an integer, final answer would be 323.
Where n is the resonance node, v is the speed of sound in air and L is the length of a cylinder.
The fundamental frequency is simply the lowest resonant frequency.
We find it by plugging in n=1:
To find what harmonic has to be excited so that it resonates at f>20Hz we simply plug in f=20 Hz and find our n:
We can see that any resonant frequency is simply a multiple of a base frequency.
Let us find which harmonic resonates with the frequency 20 Hz:
Since n has to be an integer, final answer would be 323.
The required value of the index of refraction of glass is 1.5.
Given data:
The speed of light in a vacuum is, .
The speed of light in a glass is, .
Light has the tendency to travel from one medium to another, then the difference between the speeds of light in various mediums is determined by a term, known as the index of refraction. The mathematical expression for the index of refraction of glass is,
n = c / v
Solving as
Thus, we can conclude that the required value of the index of refraction of glass is 1.5.
Learn more about the index of refraction here: