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nirvana33 [79]
3 years ago
13

What is meaning of trash​

Chemistry
2 answers:
denis23 [38]3 years ago
8 0

Answer:

Garbage, something that someone threw away.

salantis [7]3 years ago
7 0

Answer:

waste or discarded material

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A student observed a blue
morpeh [17]

Answer:

Color.

Explanation:

Hello,

In this case, since matter has a lot of properties regarding its physical condition and chemical composition, those related to the appearance of matter are physical. In such a way, since the student observed to different substances with also different colors, we can infer that the property of matter that was observed in the scenario was color, which accounts for the graphical perception we have from them.

Best regards.

5 0
3 years ago
What do all fossils fuels have in common
lys-0071 [83]

\mathrm\pink{Almost \: all \: fossils \: are \: in \: sedimentary \: rocks.}

7 0
2 years ago
The density of the fat tristearin is 0.95 g cm−3 . Calculate the change in molar Gibbs energy of tristearin when a deep-sea crea
KatRina [158]

The formula for the change in Gibbs energy of a solid is:

ΔG = Vm ΔP

where, ΔG is change in Gibbs, Vm is molar volume, ΔP is change in pressure

ΔP = P(final) – P(initial)

P(final) = 1 atm = 101325 Pa

P(initial) = ρ_water *g *h = (1030 kg/m^3) * 9.8 m/s^2 * 2000 m = 20188000 kg m/s^2 = 20188000 Pa

Vm = (950 kg/m^3) * (1000 mol / 891.48 kg) = 1065.64 mol/m^3

 

So,

ΔG = (1065.64 mol/m^3) * (101325 Pa - 20188000 Pa)

<span>ΔG = -21405164347 J = -21.4 GJ</span>

8 0
3 years ago
Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el
Dovator [93]

Answer: 406 hours

Explanation:

Q=I\times t

where Q= quantity of electricity in coloumbs

I = current in amperes = 39.5 A

t= time in seconds = ?

The deposition of copper at cathode is represented by:

Cu^{2+}+2e^-\rightarrow Cu

96500\times 2=193000 Coloumb of electricity deposits 1 mole of copper

i.e. 63.5 g of copper is deposited by = 193000 Coloumb

Thus 19.0 kg or 19000 g of copper is deposited by = \frac{193000}{63.5}\times 19000=57748032 Coloumb

57748032=39.5\times t

t=1461975sec=406hours    (1hour=3600s)

Thus it will take 406 hours to plate 19.0 kg of copper onto the cathode if the current passed through the cell is held constant at 39.5 A

3 0
3 years ago
Andrew walks through his garden and observes that the shapes of dewdrops are not always the same. Suppose he wants to investigat
Allisa [31]

Answer: A, C, E

Explanation: PLATO. all testable questions.

6 0
3 years ago
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