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GalinKa [24]
3 years ago
7

At what temperature is a gas likely to have the lowest rate of diffusion? 15° 21° 24° 30°

Chemistry
2 answers:
sergiy2304 [10]3 years ago
8 0

Answer:

At 15° the gas will have lowest rate of diffusion.

Explanation:

Temperature directly affects the kinetic energy of gas molecules. The energy of motion is called kinetic energy. So if we increase the temperature of gas the average kinetic energy of the gas molecules will increase (they will move faster). Due to increase in kinetic energy they will easily diffuse from their higher concentration to lower concentration (which is diffusion).

Hence the rate of diffusion at given temperature will have following increasing order.

15° < 21° < 24° < 30°

Ray Of Light [21]3 years ago
7 0

AT 15°

The rate of diffusion of a gas is directly proportional to the absolute temperature. At lower temperature the gas particles have less kinetic energy than at higher temperature. This makes the particles travel faster at higher temperature than lower temperature.

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Multiple choice-- 16 pts!
Naddika [18.5K]

Answer: It decreases because nonvolatile aluminum and chloride ions now occupy some of the volume of the system.

Explanation:

Vapor pressure of a liquid  is defined as the pressure exerted by the vapors  in equilibrium with the liquid/solution at a particular temperature.

So, when a non-volatile solute is added to a solvent then its molecules align at the surface of liquid. As a result, less number of solvent molecules will escape from the solution. Thus, there will be decrease in vapors and thus the vapor pressure decrease.

The relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.

6 0
3 years ago
Calculate the maximum KE and velocity of an electron from zinc by a 275nm photon
Dmitry [639]

Answer:

Kinetic energy: 6.024*10^{-20}

Velocity: 3.64*10^{5}

Explanation:

From the equations of the photo-electric effect,

We know:

hv=hv_0+K.E

Where,

1.h is the Planck's constant which is 6.626*10^{-34}

2.v,v_0 are the frequency of light emitted and threshold frequencies respectively.

3.K.E is the kinetic energy of the electrons emitted.

By fact, we come to know that the threshold frequency of Zn is 300nm

And also v=\frac{c}{d}

Where ,

1. c is the speed of light =3*10^8

2.d is the wavelength.

Thus,

\frac{hc}{d}=\frac{hc}{d_0}+K.E\\K.E=\frac{hc}{d}-\frac{hc}{d_0}\\K.E=hc*(\frac{1}{d}-\frac{1}{d_0})\\K.E=6.626*10^{-34}*3*10^8*(\frac{1}{275*10^{-9}}-\frac{1}{300*10^{-9}})\\K.E=6.024*10^{-20}kgm^2s^{-2}

Now to find velocity:

K.E=\frac{1}{2}mv^2\\v^2=1.324*10^{11}\\v=3.64*10^5

8 0
3 years ago
Which orbital indicated on the periodic table???
Romashka-Z-Leto [24]
I think it’s S umm let me know if I’m wrong but I’m. 80 precent sure it’s S
8 0
3 years ago
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How many moles of sodium sulfate are present in .100 g of the compound?
Feliz [49]

Answer:

7.040 x 10^-4 mol

Explanation:

5 0
3 years ago
Which of the following compounds has the highest boiling point.
nlexa [21]
Answer:
            1-<u>Pentanol </u>has the highest boiling point.

Explanation:
                   Boiling points of given compounds are as follow,

                 1) 2-Pentanone  =  101 °C

                 2) 1-Pentanol  =  138 °C

                 3)  Pentane  =  36.1 °C

                 4)  Pentanal  =  103 °C

Pentanol has greatest boiling point as compare to others because it involes a strongest intermolecular interactions called as hydrogen bond interactions. Remaining compounds lack the direct attachement of hydrogen to most electrnegative atom like oxygen which is present in 1-Pentanol.
4 0
3 years ago
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