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3 years ago

I smell onions.

Chemistry

2 answers:

goldenfox [79]3 years ago

5 0

Answer:

Observation

-I smell onions

-My dog weighs 45 pounds

-It is 85 degrees outside today

Predictions

-My dog will bark at the vacuum cleaner

although he has never seen it before

-My mother is going to cook spaghetti for

supper next Tuesday

-It will be a long, hot summer

Explanation:

ioda3 years ago

3 0

Observation: I smell onions, it’s 85°F outside today, my dog weighs 45 pounds,

Prediction: it will be a long hot summer
My dog wil bark... , my mother...

(I am not 100% sure)

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Consider the reaction. 2 HBr(g) ¡ H2(g) + Br2(g) a. Express the rate of the reaction in terms of the change in concentration of

Studentka2010 [4]

Answer :

(A) The rate expression will be:

$Rate=-\frac{1}{2}\frac{d[HBr]}{dt}=+\frac{d[H_2]}{dt}=+\frac{d[Br_2]}{dt}$

(B) The average rate of the reaction during this time interval is, 0.00176 M/s

(C) The amount of Br₂ (in moles) formed is, 0.0396 mol

Explanation :

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The given rate of reaction is,

$2HBr(g)\rightarrow H_2(g)+Br_2(g)$

The expression for rate of reaction :

$\text{Rate of disappearance of }HBr=-\frac{1}{2}\frac{d[HBr]}{dt}$

$\text{Rate of disappearance of }H_2=+\frac{d[H_2]}{dt}$

$\text{Rate of formation of }Br_2=+\frac{d[Br_2]}{dt}$

Part A:

The rate expression will be:

$Rate=-\frac{1}{2}\frac{d[HBr]}{dt}=+\frac{d[H_2]}{dt}=+\frac{d[Br_2]}{dt}$

Part B:

$\text{Average rate}=-\frac{1}{2}\frac{d[HBr]}{dt}$

$\text{Average rate}=-\frac{1}{2}\frac{(0.512-0.600)M}{(25.0-0.0)s}$

$\text{Average rate}=0.00176M/s$

The average rate of the reaction during this time interval is, 0.00176 M/s

Part C:

As we are given that the volume of the reaction vessel is 1.50 L.

$\frac{d[Br_2]}{dt}=0.00176M/s$

$\frac{d[Br_2]}{15.0s}=0.00176M/s$

$[Br_2]=0.00176M/s\times 15.0s$

$[Br_2]=0.0264M$

Now we have to determine the amount of Br₂ (in moles).

$\text{Moles of }Br_2=\text{Concentration of }Br_2\times \text{Volume of solution}$

$\text{Moles of }Br_2=0.0264M\times 1.50L$

$\text{Moles of }Br_2=0.0396mol$

The amount of Br₂ (in moles) formed is, 0.0396 mol

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3 years ago

Chlorination of 2-butanone yields two isomeric products, each having the molecular formula C4H7ClO.

Nat2105 [25]

Answer:

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Explanation:

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3. Other researchers also racing to find the structure include;

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2 years ago

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11Alexandr11 [23.1K]

$work \: = force \times displacement$
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2 years ago

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Answer:

Physical change since evaporation occurs

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3 years ago